• 剑指Offer之按顺时针打印数组


    题目描述

      输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

    Java代码

    package com.swordOffer.printMatrix13;
    
    import java.util.Scanner;
    
    /**
     * Created by Feng on 2017/5/8.
     * 输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,
     * 例如,如果输入如下矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
     * 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.
     */
    public class PrintMatrix {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            while (sc.hasNext()) {
                String nums = sc.nextLine();
                int row = Integer.parseInt(nums.split(" ")[0]);//数组的行数
                int column = Integer.parseInt(nums.split(" ")[1]);//数组的列数
    
                int[][] matrix = new int[row][column];
                for (int i = 0; i < row; i++) {
                    for (int j = 0; j < column; j++) {
                        matrix[i][j] = sc.nextInt();
                    }
                }
    
                printMatrixClockwisely(matrix, column, row);
            }
        }
    
        public static void printMatrixClockwisely(int[][] marix, int column, int row) {
    
            //判断是否为空
            if (marix == null || column <= 0 || row <= 0) {
                return;
            }
    
            int start = 0;
            while (column > start * 2 && row > start * 2) {
                printMatrixInCircle(marix, column, row, start);
                start++;
            }
        }
    
        public static void printMatrixInCircle(int[][] matrix, int column, int row, int start) {
    
            int endX = column - 1 - start;
            int endY = row - 1 - start;
    
            //从左到右打印一行
            for (int i = start; i <= endX; i++) {
                int number = matrix[start][i];
                System.out.print(number + "	");
            }
    
            //从上到下打印一列
            if (start < endY) {
                for (int i = start + 1; i <= endY; i++) {
                    int number = matrix[i][endX];
                    System.out.print(number + "	");
                }
            }
    
            //从右到左打印一行
            if (start < endX && start < endY) {
                for (int i = endX - 1; i >= start; i--) {
                    int number = matrix[endY][i];
                    System.out.print(number + "	");
                }
            }
    
            //从下到上打印一列
            if (start < endX && start < endY) {
                for (int i = endY - 1; i >= start + 1; i--) {
                    int number = matrix[i][start];
                    System.out.print(number + "	");
                }
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/lfeng1205/p/6827762.html
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