Description
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
Example
For example,
Given input array nums = [1,1,2],
Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the new length.
思路
- 去重问题没啥好说的吧
- 一个下标为去重后的索引,一个下标是去重前的索引
代码
class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int len = nums.size();
if(len <= 1) return len;
int begin = -1, i = 0;
while(i < len){
if(i > 0 && nums[i] == nums[i - 1]){
++i;
continue;
}
++begin;
nums[begin] = nums[i];
++i;
}
return begin + 1;
}
};