• 33.求1*2+2*3+3*4+……前n项的和


    #include<iostream>
    using namespace std;
    int XiangCheng(int );
    
    int main()
    {
        int n,sum=0;
        cout<<"please input an number : "<<endl;
        cin>>n;
        for(int i=1;i<=n;i++)
        {
            sum+=XiangCheng(i);
        }
        cout<<"the answer is : "<<sum<<endl;
        return 0;
    }
    
    int XiangCheng(int index)
    {
        int m;
        m=index*(index+1);
        return m;
    }
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  • 原文地址:https://www.cnblogs.com/jixiaowu/p/3896783.html
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