• XNA 跳跃简单算法和代码


    刚一个朋友问跳跃怎么实现,其实对xna我也不了解,Zzk里搜索“XNA 跳跃”居然没有符合的记录,惊讶之余也有点冲动要不自己也搞一个?不过xna真的是不懂啊,找了两三个源码,笔者实在笨,没能理解它的算法实在见笑了。干脆自己动手从头实现一个,先从现实考虑起跳要考虑的因素是起跳速度(v1)体重(w)重力g然后根据物理xxx记不得了,咱不好高骛远了,simple is perfect 直接上代码:

    全局参数:

            private bool _isJumping;
            private bool _jumpKeyDown;
            private float _jumpHeight = 100f;
            private TimeSpan _jumpTimeSpan = TimeSpan.FromMilliseconds(500);
            private double _jumpStartTime;
            private float _jumpStartPosition;
    

     Update中的代码:

    _jumpKeyDown = Keyboard.GetState().IsKeyDown(Keys.Space);
                squarePosition.Y = DoJump(squarePosition.Y, gameTime);
    

     高度算法函数:

            private float DoJump(float velocityY, GameTime gameTime)
            {
                if (_jumpKeyDown && !_isJumping)
                {
                    _isJumping = true;
                    _jumpStartTime = gameTime.TotalGameTime.TotalMilliseconds;
                    _jumpStartPosition = velocityY;
                }
                if (_isJumping)
                {
                    var jumpTime = gameTime.TotalGameTime.TotalMilliseconds - _jumpStartTime;
                    var topTime = _jumpTimeSpan.TotalMilliseconds / 2;
                    if (jumpTime < _jumpTimeSpan.TotalMilliseconds)
                    {
                        if (jumpTime > topTime)
                        {
                            velocityY =
                                _jumpStartPosition-_jumpHeight - Convert(-(jumpTime - topTime) * _jumpHeight / (_jumpTimeSpan.TotalMilliseconds - topTime));
                        }
                        else
                        {
                            velocityY =_jumpStartPosition+ Convert(-( jumpTime)*_jumpHeight/topTime);
                        }
                    }
                    else
                    {
                        _isJumping = false;
                        velocityY = _jumpStartPosition;
                    }
    
                }
                return velocityY;
            }
    
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  • 原文地址:https://www.cnblogs.com/jinzhao/p/2533297.html
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