题解
读错题了,是最后留下一个牛人首长歌颂他,和其他人没有关系,t就相当于数据组数
结论题,具体可看
https://www.zhihu.com/question/59895916/answer/196874145
最后一个求导(1 - z)不拆,最后代入1的时候会消掉,就得出了这个结论
代码
#include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <map>
//#define ivorysi
#define pb push_back
#define space putchar(' ')
#define enter putchar('
')
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define mo 974711
#define RG register
#define MAXN 200005
using namespace std;
typedef long long int64;
typedef double db;
template<class T>
void read(T &res) {
res = 0;char c = getchar();T f = 1;
while(c < '0' || c > '9') {
if(c == '-') f = -1;
c = getchar();
}
while(c >= '0' && c <= '9') {
res = res * 10 + c - '0';
c = getchar();
}
res *= f;
}
template<class T>
void out(T x) {
if(x < 0) putchar('-'),x = -x;
if(x >= 10) out(x / 10);
putchar('0' + x % 10);
}
const int MOD = 10000;
int fpow(int x,int c) {
int res = 1,t = x % MOD;
while(c) {
if(c & 1) res = res * t % MOD;
t = t * t % MOD;
c >>= 1;
}
return res;
}
int N,T,M,a[100005],fail[100005];
void Solve() {
read(N);read(T);
while(T--) {
read(M);
for(int i = 1 ; i <= M ; ++i) read(a[i]);
fail[1] = 0;
for(int i = 2 ; i <= M ; ++i) {
int p = fail[i - 1];
while(p && a[p + 1] != a[i]) p = fail[p];
if(a[p + 1] == a[i]) fail[i] = p + 1;
else fail[i] = 0;
}
int p = M,ans = 0;
while(p) {
ans += fpow(N,p);
p = fail[p];
}
ans %= MOD;
printf("%04d
",ans);
}
}
int main() {
#ifdef ivorysi
freopen("f1.in","r",stdin);
#endif
Solve();
return 0;
}