• SQL自定义函数split分隔字符串


    一、F_Split:分割字符串拆分为数据表

    复制代码
    Create FUNCTION [dbo].[F_Split]
     (
         @SplitString nvarchar(max),  --源字符串
         @Separator nvarchar(10)=' '  --分隔符号,默认为空格
     )
     RETURNS @SplitStringsTable TABLE  --输出的数据表
    ( [id] int identity(1,1), [value] nvarchar(max) ) AS BEGIN DECLARE @CurrentIndex int; DECLARE @NextIndex int; DECLARE @ReturnText nvarchar(max); SELECT @CurrentIndex=1; WHILE(@CurrentIndex<=len(@SplitString)) BEGIN SELECT @NextIndex=charindex(@Separator,@SplitString,@CurrentIndex); IF(@NextIndex=0 OR @NextIndex IS NULL) SELECT @NextIndex=len(@SplitString)+1; SELECT @ReturnText=substring(@SplitString,@CurrentIndex,@NextIndex-@CurrentIndex); INSERT INTO @SplitStringsTable([value]) VALUES(@ReturnText); SELECT @CurrentIndex=@NextIndex+1; END RETURN; END --使用示例 select * FROm dbo.F_Split('111,b2222,323232,32d,e,323232f,g3222', ',')
    复制代码

    结果为

    id          value

    -------- ---------------------------------------

    1           111

    2           b2222

    3           323232

    4           32d

    5           e

    6           323232f

    7           g3222


    =========================================================================

    二、F_SplitLength:获取分割后的字符数组的长度

    复制代码
    Create function [dbo].[F_SplitLength]
     (
      @String nvarchar(max),  --要分割的字符串
      @Split nvarchar(10)  --分隔符号
     )
     returns int
     as
     begin
      declare @location int
      declare @start int
      declare @length int
      
      set @String=ltrim(rtrim(@String))
      set @location=charindex(@split,@String)
      set @length=1
      while @location<>0
      begin
        set @start=@location+1
        set @location=charindex(@split,@String,@start)
        set @length=@length+1
      end
      return @length
     end
    
    --调用示例
    select dbo.F_SplitLength('111,b2222,323232,32d,e,323232f,g3222',',')
    复制代码

    结果为7。

    =========================================================================

    三、F_SplitOfIndex:获取分割后特定索引的字符串

    复制代码
    Create function [dbo].[F_SplitOfIndex]
     (
      @String nvarchar(max),  --要分割的字符串
      @split nvarchar(10),  --分隔符号
      @index int --取第几个元素
     )
     returns nvarchar(1024)
     as
     begin
      declare @location int
      declare @start int
      declare @next int
      declare @seed int
      
      set @String=ltrim(rtrim(@String))
      set @start=1
      set @next=1
      set @seed=len(@split)   
      set @location=charindex(@split,@String)
      
      while @location<>0 and @index>@next
      begin
        set @start=@location+@seed
        set @location=charindex(@split,@String,@start)
        set @next=@next+1
      end
      if @location =0 select @location =len(@String)+1   
      return substring(@String,@start,@location-@start)
     end
    
    --使用示例
    select dbo.F_SplitOfIndex('111,b2222,323232,32d,e,323232f,g3222',',', 3)
    复制代码

    结果为323232。

    转自:http://www.cnblogs.com/xiaofengfeng/archive/2012/06/01/2530930.html

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  • 原文地址:https://www.cnblogs.com/itjeff/p/5687607.html
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