一、F_Split:分割字符串拆分为数据表
Create FUNCTION [dbo].[F_Split]
(
@SplitString nvarchar(max), --源字符串
@Separator nvarchar(10)=' ' --分隔符号,默认为空格
)
RETURNS @SplitStringsTable TABLE --输出的数据表
(
[id] int identity(1,1),
[value] nvarchar(max)
)
AS
BEGIN
DECLARE @CurrentIndex int;
DECLARE @NextIndex int;
DECLARE @ReturnText nvarchar(max);
SELECT @CurrentIndex=1;
WHILE(@CurrentIndex<=len(@SplitString))
BEGIN
SELECT @NextIndex=charindex(@Separator,@SplitString,@CurrentIndex);
IF(@NextIndex=0 OR @NextIndex IS NULL)
SELECT @NextIndex=len(@SplitString)+1;
SELECT @ReturnText=substring(@SplitString,@CurrentIndex,@NextIndex-@CurrentIndex);
INSERT INTO @SplitStringsTable([value]) VALUES(@ReturnText);
SELECT @CurrentIndex=@NextIndex+1;
END
RETURN;
END
--使用示例
select * FROm dbo.F_Split('111,b2222,323232,32d,e,323232f,g3222', ',')
结果为
id value
-------- ---------------------------------------
1 111
2 b2222
3 323232
4 32d
5 e
6 323232f
7 g3222
=========================================================================
二、F_SplitLength:获取分割后的字符数组的长度
Create function [dbo].[F_SplitLength]
(
@String nvarchar(max), --要分割的字符串
@Split nvarchar(10) --分隔符号
)
returns int
as
begin
declare @location int
declare @start int
declare @length int
set @String=ltrim(rtrim(@String))
set @location=charindex(@split,@String)
set @length=1
while @location<>0
begin
set @start=@location+1
set @location=charindex(@split,@String,@start)
set @length=@length+1
end
return @length
end
--调用示例
select dbo.F_SplitLength('111,b2222,323232,32d,e,323232f,g3222',',')
结果为7。
=========================================================================
三、F_SplitOfIndex:获取分割后特定索引的字符串
Create function [dbo].[F_SplitOfIndex]
(
@String nvarchar(max), --要分割的字符串
@split nvarchar(10), --分隔符号
@index int --取第几个元素
)
returns nvarchar(1024)
as
begin
declare @location int
declare @start int
declare @next int
declare @seed int
set @String=ltrim(rtrim(@String))
set @start=1
set @next=1
set @seed=len(@split)
set @location=charindex(@split,@String)
while @location<>0 and @index>@next
begin
set @start=@location+@seed
set @location=charindex(@split,@String,@start)
set @next=@next+1
end
if @location =0 select @location =len(@String)+1
return substring(@String,@start,@location-@start)
end
--使用示例
select dbo.F_SplitOfIndex('111,b2222,323232,32d,e,323232f,g3222',',', 3)
结果为323232。
转自:http://www.cnblogs.com/xiaofengfeng/archive/2012/06/01/2530930.html