Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
Solution 1:recursion,the key is to find out all situations of return true and false
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(!p && !q)return true; if(p && !q)return false; if(!p && q)return false; if(isSameTree(p->left, q->left) && isSameTree(p->right, q->right) && p->val==q->val)return true; return false; } };
Solution 2: 非递归,待续