The end of other

The end of other

For language training our Robots want to learn about suffixes.

In this task, you are given a set of words in lower case. Check whether there is a pair of words, such that one word is the end of another (a suffix of another). For example: {"hi", "hello", "lo"} -- "lo" is the end of "hello", so the result is True.

Hints: For this task you should know how to iterate through set types and string data type functions. Read more about set type here and string functions here.

Input: Words as a set of strings.

Output: True or False, as a boolean.

题目大义：给出一个含有单词的集合（set），如果某个单词是另一个单词的后缀，如"lo"是"hello"的后缀，则返回True，如果不存在则返回False。

一开始认为set可以使用index，就像数组般使用，可惜了，set并不支持。想想也合理，c++中的set也是不支持[]索引的，于是乎想到了for xx in xx形式，加上提示：str.endswith(suffix[, start[, end]])，恍然大悟，给出拙劣的Python代码

1 def checkio(words_set):
2     for words in words_set:
3         for other_words in words_set:
4             if other_words != words and other_words.endswith(words):
5                 return True
6     
7     return False