• hdu 5620


    KK's Steel

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
    Total Submission(s): 197    Accepted Submission(s): 90


    Problem Description
    Our lovely KK has a difficult mathematical problem:he has a N(1N1018) meters steel,he will cut it into steels as many as possible,and he doesn't want any two of them be the same length or any three of them can form a triangle.
     
    Input
    The first line of the input file contains an integer T(1T10) , which indicates the number of test cases.

    Each test case contains one line including a integer N(1N1018) ,indicating the length of the steel.
     
    Output
    For each test case, output one line, an integer represent the maxiumum number of steels he can cut it into.
     
    Sample Input
    1 6
     
    Sample Output
    3
    Hint
    1+2+3=6 but 1+2=3 They are all different and cannot make a triangle.
     
    Source
     
    题意: n米长的钢管切成若干段 要求每段 长度不同 且任意三段不能组成三角形 问最多能分成多少段
    题解: 易发现 满足斐波那契数列
     
      
    #include<iostream>
    #include<cstdio>
    #define LL __int64
    using namespace std;
    int main()
    {
        int t;
        LL n;
        scanf("%d",&t);
        for(int i=1;i<=t;i++)
        {
            scanf("%I64d",&n);
            LL exm=1;
            LL ans=0;
            LL flag=1;
            while(n>=exm)
            {
                LL gg;
                gg=exm;
              ans++;
              n-=exm;
              exm+=flag;
              flag=gg;
              //cout<<flag<<" "<<exm<<endl;
            }
            printf("%I64d
    ",ans);
        }
        return 0;
    }
    

      

  • 相关阅读:
    UVa 116 单向TSP(多段图最短路)
    POJ 1328 Radar Installation(贪心)
    POJ 1260 Pearls
    POJ 1836 Alignment
    POJ 3267 The Cow Lexicon
    UVa 1620 懒惰的苏珊(逆序数)
    POJ 1018 Communication System(DP)
    UVa 1347 旅行
    UVa 437 巴比伦塔
    UVa 1025 城市里的间谍
  • 原文地址:https://www.cnblogs.com/hsd-/p/5184964.html
Copyright © 2020-2023  润新知