信号灯法
//测试生产者消费者问题2:信号灯法,标志位解决
public class TestPc2 {
public static void main(String[] args) {
TV tv = new TV();
new Player(tv).start();
new Watcher(tv).start();
}
}
//生产者-->演员
class Player extends Thread{
TV tv;
public Player(TV tv){
this.tv = tv;
}
@Override
public void run() {
for (int i = 0; i < 20; i++) {
if (i%2==0){
this.tv.play("快乐大本营播放中");
}else {
this.tv.play("抖音:记录美好生活");
}
}
}
}
//消费者-->观众
class Watcher extends Thread{
TV tv;
public Watcher(TV tv){
this.tv = tv;
}
@Override
public void run() {
for (int i = 0; i < 20; i++) {
tv.watch();
}
}
}
//产品-->节目
class TV{
//演员表演,观众等待
//观众观看,演员等待
String voice;//表演的节目
boolean flag = true;
//表演
public synchronized void play(String voice){
if (!flag){
try {
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("演员表演了:"+voice);
//通知观众观看
this.notifyAll();//通知唤醒
this.voice = voice;
this.flag = !this.flag;
}
//观看
public synchronized void watch(){
if (flag){
try {
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("观看了:"+voice);
//通知演员表演
this.notifyAll();
this.flag = !this.flag;
}
}