• leetcode(c++)(单调序列)


    #include <iostream>
    #include <vector>
    #include <queue>
    using namespace std;
    
    vector<int>maxSlidingWindow(const vector<int>& nums,int k)
    {
        int n = nums.size();
        deque<int>q;
        vector<int>res(n-k+1);
        for(int i = 0; i < n; ++i)
        {
            int start = i-k+1;
            while(!q.empty() && i - q.front() >= k)q.pop_front();
            while(!q.empty() && nums[q.front()] <= nums[i])q.pop_back();
            q.push_back(i);
            if(start >= 0)res[start] = nums[q.front()];
        }
        return res;
    }
    
    void print(const vector<int>& nums)
    {
        for(auto num : nums)
        {
            cout << num << " ";
        }
        cout << endl;
    }
    
    int shortestSubarray(const vector<int>& A, int k)
    {
        int n = A.size(),res = n + 1;
        vector<int>sum(n + 1);
        for(int i = 0; i < n; ++i)
        {
            sum[i+1] = sum[i] + A[i];
        }
        deque<int>q;
        for(int i = 0; i < n + 1 ; ++i)
        {
            while(!q.empty() && sum[i] - sum[q.front()] >= k)
            {
                res = min(res,i - q.front());
                q.pop_front();
            }
            while(!q.empty() && sum[q.front()] >= sum[i])q.pop_back();
            q.push_back(i);        
        }
        return res <= n ? res : -1;
    }
    
    int constrainedSubSum(const vector<int>& nums,int k)
    {
        deque<int>q;
        int n = nums.size();
        vector<int>sum(n);
        int res = sum[0];
        for(int i = 0; i < n; ++i)
        {
            sum[i] = nums[i];
            if(!q.empty())sum[i]+=sum[q.front()];
            res = max(res,sum[i]);
            if(!q.empty() && i - q.front() >= k)q.pop_front();
            while(!q.empty() && sum[q.back()] <= sum[i])q.pop_back();
            if(sum[i] > 0)q.push_back(i);
        }
        return res;
    }
    
    int longestSubarry(const vector<int>& A,int limit)
    {
        deque<int>maxd,mind;
        int left = 0, res = 0;
        for(int i = 0 ; i < A.size(); ++i)
        {
            while(!maxd.empty() && maxd.back() < A[i])maxd.pop_back();
            while(!mind.empty() && A[i] < mind.front())mind.pop_back();
            maxd.push_back(A[i]);
            mind.push_back(A[i]);
            if(maxd.front() - mind.front() > limit)
            {
                if(maxd.front() == A[left])maxd.pop_front();
                if(mind.front() == A[left])mind.pop_front();
                ++left;
            }
            res = max(res,i - left + 1);
        }    
        return res;
    }
    
    int maxResult(const vector<int>& nums,int k)
    {
        int n = nums.size();
        vector<int>dp(n);
        dp[0] = nums[0];
        deque<int>q;
        q.push_back(0);
        for(int i = 0; i < n - 1;++i)
        {
            while(!q.empty() && i - q.front() >= k)q.pop_front();
            while(!q.empty() && dp[q.front()] <= dp[i])q.pop_back();
            q.push_back(i);
            dp[i+1]=dp[q.front()] + nums[i + 1]; 
        }
        return dp[n-1];
    }
    
    int main()
    {
        //LeetCode239
        vector<int>nums{1,3,-1,-3,5,3,6,7};
        int k = 3;
        print(maxSlidingWindow(nums,k));
    
        //LeetCode862
        vector<int>A{1,2};
        k = 2;
        cout << shortestSubarray(A,k) << endl;
    
        //LeetCode1425
        nums = {10,2,-10,5,20};
        k = 2;
        cout << constrainedSubSum(nums,k) << endl;
    
        //LeetCode1438
        nums = {8,2,4,7};
        k = 4;
        cout << longestSubarry(nums,k) << endl;
    
        //LeetCode1696
        nums ={1,-1,-2,4,-7,3};
        k = 2;
        cout << maxResult(nums,k) << endl;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/fourmi/p/16254380.html
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