一 单表查询的语法
语法顺序
SELECT 字段1,字段2... FROM 表名 WHERE 条件 GROUP BY field HAVING 筛选 ORDER BY field LIMIT 限制条数
二 关键字的执行优先级(重点)
关键字的执行优先级:
from
where
group by
having
select
distinct
order by
limit
1.找到表:from
2.拿着where指定的约束条件,去文件/表中取出一条条记录
3.将取出的一条条记录进行分组group by,如果没有group by,则整体作为一组
4.将分组的结果进行having过滤
5.执行select
6.去重
7.将结果按条件排序:order by
8.限制结果的显示条数
三 简单查询
准备表和记录
company.employee 员工id id int 姓名 emp_name varchar 性别 sex enum 年龄 age int 入职日期 hire_date date 岗位 post varchar 职位描述 post_comment varchar 薪水 salary double 办公室 office int 部门编号 depart_id int #创建表 create table employee( id int not null unique auto_increment, name varchar(20) not null, sex enum('male','female') not null default 'male', #大部分是男的 age int(3) unsigned not null default 28, hire_date date not null, post varchar(50), post_comment varchar(100), salary double(15,2), office int, # 一个部门一个屋子 depart_id int ); #查看表结构 mysql> desc employee; +--------------+-----------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-----------------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(20) | NO | | NULL | | | sex | enum('male','female') | NO | | male | | | age | int(3) unsigned | NO | | 28 | | | hire_date | date | NO | | NULL | | | post | varchar(50) | YES | | NULL | | | post_comment | varchar(100) | YES | | NULL | | | salary | double(15,2) | YES | | NULL | | | office | int(11) | YES | | NULL | | | depart_id | int(11) | YES | | NULL | | +--------------+-----------------------+------+-----+---------+----------------+ #插入记录 #三个部门:教学,销售,运营 insert into employee(name,sex,age,hire_date,post,salary,office,depart_id) values ('alice','female',18,'20170301','teacher',7300.33,401,1), #以下是教学部 ('nico','female',78,'20150302','teacher',1000000.31,401,1), ('anna','female',81,'20130305','teacher',8300,401,1), ('jack','male',73,'20140701','teacher',3500,401,1), ('liwenzhou','male',28,'20121101','teacher',2100,401,1), ('jingliyang','female',18,'20110211','teacher',9000,401,1), ('jinxin','male',18,'19000301','teacher',30000,401,1), ('成龙','male',48,'20101111','teacher',10000,401,1), ('歪歪','female',48,'20150311','sale',3000.13,402,2),#以下是销售部门 ('丫丫','female',38,'20101101','sale',2000.35,402,2), ('丁丁','female',18,'20110312','sale',1000.37,402,2), ('星星','female',18,'20160513','sale',3000.29,402,2), ('格格','female',28,'20170127','sale',4000.33,402,2), ('张野','male',28,'20160311','operation',10000.13,403,3), #以下是运营部门 ('程咬金','male',18,'19970312','operation',20000,403,3), ('程咬银','female',18,'20130311','operation',19000,403,3), ('程咬铜','male',18,'20150411','operation',18000,403,3), ('程咬铁','female',18,'20140512','operation',17000,403,3) ; #ps:如果在windows系统中,插入中文字符,select的结果为空白,可以将所有字符编码统一设置成gbk
#简单查询 SELECT id,name,sex,age,hire_date,post,post_comment,salary,office,depart_id FROM employee; SELECT * FROM employee; SELECT name,salary FROM employee; #避免重复DISTINCT SELECT DISTINCT post FROM employee; #通过四则运算查询 SELECT name, salary*12 FROM employee; # 查年薪(内存中的虚拟表)annual_salary为表名(不加as也可以) SELECT name, salary*12 AS Annual_salary FROM employee; SELECT name, salary*12 Annual_salary FROM employee; #定义显示格式 CONCAT() 函数用于连接字符串 SELECT CONCAT('姓名: ',name,' 年薪: ', salary*12) AS Annual_salary FROM employee; SELECT CONCAT('姓名: ',name,' 年薪: ', salary*12) AS Annual_salary,post FROM employee; # 再加一个职位字段 SELECT CONCAT('姓名: ',name,' 性别: ', sex) AS Info, CONCAT("薪资": ',salary*12 ) AS Annual_salary FROM employee; CONCAT_WS() 第一个参数为分隔符 SELECT CONCAT_WS(':',name,sex,age) AS Annual_salary FROM employee; #显示“姓名:性别:年龄” 结合CASE语句: SELECT ( CASE WHEN NAME = 'egon' THEN NAME WHEN NAME = 'alex' THEN CONCAT(name,'_BIGSB') ELSE concat(NAME, 'SB') END ) as new_name FROM emp;
select distinct post from employee; # 查询职位,去重 # 四则运算 select name,salary*12 as annual_salary from employee # 查年薪(内存中的虚拟表)annual_salary为表名(不加as也可以) #自己规定格式 select concat() from employee;
小练习:
1 查出所有员工的名字,薪资,格式为 <名字:egon> <薪资:3000> 2 查出所有的岗位(去掉重复) 3 查出所有员工名字,以及他们的年薪,年薪的字段名为annual_year
select concat('<名字:',name,'> ','<薪资:',salary,'>') from employee; select distinct depart_id from employee; select name,salary*12 annual_salary from employee;
四 WHERE约束
where字句中可以使用:
1. 比较运算符:> < >= <= <> !=
2. between 80 and 100 值在80到100之间
3. in(80,90,100) 值是80或90或100
4. 模糊匹配 like 'abc%'
pattern可以是%或_,
%表示任意多字符
_表示一个字符
5. 逻辑运算符:在多个条件直接可以使用逻辑运算符 and or not
#1:单条件查询
SELECT name FROM employee
WHERE post='sale';
#2:多条件查询
SELECT name,post,salary FROM employee
WHERE post='teacher' AND salary>10000; # 找出薪资大于10000的老师
#3:关键字BETWEEN AND (本质就是大于等于和小于等于)
SELECT name,salary FROM employee
WHERE salary BETWEEN 10000 AND 20000; # 找出薪资在10000和20000的老师
SELECT name,salary FROM employee
WHERE salary NOT BETWEEN 10000 AND 20000; # 找出薪资小于10000和大于20000的老师
#4:关键字IS NULL(判断某个字段是否为NULL不能用等号,需要用IS)
SELECT name,post_comment FROM employee
WHERE post_comment IS NULL;
SELECT name,post_comment FROM employee
WHERE post_comment IS NOT NULL;
SELECT name,post_comment FROM employee
WHERE post_comment=''; 注意''是空字符串,不是null
ps:
执行
update employee set post_comment='' where id=2;
再用上条查看,就会有结果了
#5:关键字IN集合查询
SELECT name,age,salary FROM employee
WHERE age=73 OR age=81 OR age=28; #找出年龄是73或者81或者28的
SELECT name,age,salary FROM employee
WHERE age IN (73,28,81) ; # 上述的简单方法
SELECT name,age,salary FROM employee
WHERE age NOT IN (73,28,81) ;
#6:关键字LIKE模糊查询
通配符’%’
SELECT * FROM employee
WHERE name LIKE 'al%'; # 名字是al开头,%任意多个字符
通配符’_’
SELECT * FROM employee
WHERE name LIKE 'j__'; # _ 任意一个字符(可以用多个)
小练习:
1. 查看岗位是teacher的员工姓名、年龄 2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄 3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资 4. 查看岗位描述不为NULL的员工信息 5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资 6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资 7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪
select name,age from employee where post = 'teacher'; select name,age from employee where post='teacher' and age > 30; select name,age,salary from employee where post='teacher' and salary between 9000 and 10000; select * from employee where post_comment is not null; select name,age,salary from employee where post='teacher' and salary in (10000,9000,30000); select name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000); select name,salary*12 from employee where post='teacher' and name like 'jin%';
五 分组查询:GROUP BY
#1、分组发生在where之后,即分组是基于where之后得到的记录而进行的 #2、分组指的是:将所有记录按照某个相同字段进行归类,比如针对员工信息表的职位分组,或者按照性别进行分组等 #3、为何要分组呢? 取每个部门的最高工资 取每个部门的员工数 取男人数和女人数 小窍门:‘每’这个字后面的字段,就是我们分组的依据 #4、大前提: 可以按照任意字段分组,但是分组完毕后,比如group by post,只能查看post字段,如果想查看组内信息,需要借助于聚合函数
ONLY_FULL_GROUP_BY
SQL_MODE设置
#查看MySQL 5.7默认的sql_mode如下: mysql> select @@global.sql_mode; ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION #!!!注意 ONLY_FULL_GROUP_BY的语义就是确定select target list中的所有列的值都是明确语义,简单的说来,在ONLY_FULL_GROUP_BY模式下,target list中的值要么是来自于聚集函数的结果,要么是来自于group by list中的表达式的值。 #设置sql_mole如下操作(我们可以去掉ONLY_FULL_GROUP_BY模式): mysql> set global sql_mode='STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION';
mysql> select @@global.sql_mode; +-------------------+ | @@global.sql_mode | +-------------------+ | | +-------------------+ 1 row in set (0.00 sec) mysql> select * from employee group by post; +----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+ | 14 | 张野 | male | 28 | 2016-03-11 | operation | NULL | 10000.13 | 403 | 3 | | 9 | 歪歪 | female | 48 | 2015-03-11 | sale | NULL | 3000.13 | 402 | 2 | | 1 | alice | female | 18 | 2017-03-01 | teacher | NULL | 7300.33 | 401 | 1 | +----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+ 3 rows in set (0.55 sec) #由于没有设置ONLY_FULL_GROUP_BY,于是也可以有结果,默认都是组内的第一条记录,但其实这是没有意义的。只能取分组的字段 mysql> set global sql_mode='ONLY_FULL_GROUP_BY'; Query OK, 0 rows affected (0.00 sec) mysql> quit #设置成功后,一定要退出,然后重新登录方可生效 Bye mysql> use db1; Database changed mysql> select * from employee group by post; #报错 ERROR 1055 (42000): 'db1.emp.id' isn't in GROUP BY mysql> select post,count(id) as emp_count from employee group by post; #分组之后只能查看分组依据和使用聚合函数 +-----------+-----------+ | post | emp_count | +-----------+-----------+ | operation | 5 | | sale | 5 | | teacher | 8 | +-----------+-----------+ 3 rows in set (0.00 sec)
聚合函数 max,min,avg,sum,count
# 每个职位有多少员工 select post,count(id) as emp_count from employee group by post; #每个部门的最高工资 select post,max(salary) as emp_max_salary from employee group by post; #每个部门的最低工资 select post,min(id) as emp_min_salary from employee group by post; #每个部门的平均工资 select post,avg(id) as emp_avg_salary from employee group by post; #每个部门的年龄总和 select post,sum(age) as emp_age_total from employee group by post;
GROUP BY
单独使用GROUP BY关键字分组 SELECT post FROM employee GROUP BY post; 注意:我们按照post字段分组,那么select查询的字段只能是post,想要获取组内的其他相关信息,需要借助函数 GROUP BY关键字和GROUP_CONCAT()函数一起使用 SELECT post,GROUP_CONCAT(name) FROM employee GROUP BY post;#按照岗位分组,并查看组内成员名 SELECT post,GROUP_CONCAT(name) as emp_members FROM employee GROUP BY post; GROUP BY与聚合函数一起使用 select post,count(id) as count from employee group by post;#按照岗位分组,并查看每个组有多少人
注意:
如果我们用unique的字段作为分组的依据,则每一条记录自成一组,这种分组没有意义。
多条记录之间的某个字段值相同,该字段通常用来作为分组的依据。
没有group by则默认整体算一组
聚合函数
#强调:聚合函数聚合的是组的内容,若是没有分组,则默认一组 示例: SELECT COUNT(*) FROM employee; SELECT COUNT(*) FROM employee WHERE depart_id=1; SELECT MAX(salary) FROM employee; SELECT MIN(salary) FROM employee; SELECT AVG(salary) FROM employee; SELECT SUM(salary) FROM employee; SELECT SUM(salary) FROM employee WHERE depart_id=3;
小练习:
1. 查询岗位名以及岗位包含的所有员工名字
2. 查询岗位名以及各岗位内包含的员工个数
3. 查询公司内男员工和女员工的个数
4. 查询岗位名以及各岗位的平均薪资
5. 查询岗位名以及各岗位的最高薪资
6. 查询岗位名以及各岗位的最低薪资
7. 查询男员工与男员工的平均薪资,女员工与女员工的平均薪资
#题1:分组 mysql> select post,group_concat(name) from employee group by post; +-----------+---------------------------------------------------------+ | post | group_concat(name) | +-----------+---------------------------------------------------------+ | operation | 程咬铁,程咬铜,程咬银,程咬金,张野 | | sale | 格格,星星,丁丁,丫丫,歪歪 | | teacher | 成龙,jinxin,jingliyang,liwenzhou,jack,anna,nico,alice | +-----------+---------------------------------------------------------+ 3 rows in set (0.55 sec) #题目2: mysql> select post,count(id) from employee group by post; +-----------+-----------+ | post | count(id) | +-----------+-----------+ | operation | 5 | | sale | 5 | | teacher | 8 | +-----------+-----------+ 3 rows in set (0.00 sec) #题目3: mysql> select sex,count(id) from employee group by sex; +--------+-----------+ | sex | count(id) | +--------+-----------+ | male | 7 | | female | 11 | +--------+-----------+ 2 rows in set (0.00 sec) #题目4: mysql> select post,avg(salary) from employee group by post; +-----------+---------------+ | post | avg(salary) | +-----------+---------------+ | operation | 16800.026000 | | sale | 2600.294000 | | teacher | 133775.080000 | +-----------+---------------+ 3 rows in set (0.00 sec) #题目5 mysql> select post,max(salary) from employee group by post; +-----------+-------------+ | post | max(salary) | +-----------+-------------+ | operation | 20000.00 | | sale | 4000.33 | | teacher | 1000000.31 | +-----------+-------------+ 3 rows in set (0.00 sec) #题目6 mysql> select post,min(salary) from employee group by post; +-----------+-------------+ | post | min(salary) | +-----------+-------------+ | operation | 10000.13 | | sale | 1000.37 | | teacher | 2100.00 | +-----------+-------------+ 3 rows in set (0.00 sec) #题目七 mysql> select sex,avg(salary) from employee group by sex; +--------+--------------+ | sex | avg(salary) | +--------+--------------+ | male | 13371.447143 | | female | 97600.191818 | +--------+--------------+ 2 rows in set (0.00 sec)
六 HAVING过滤
HAVING与WHERE的区别
#执行优先级从高到低:where > group by > having
#1. Where 发生在分组group by之前,因而Where中可以有任意字段,但是绝对不能使用聚合函数。
#2. Having发生在分组group by之后,因而Having中可以使用分组的字段,无法直接取到其他字段,可以使用聚合函数
mysql> select @@sql_mode; +--------------------+ | @@sql_mode | +--------------------+ | ONLY_FULL_GROUP_BY | +--------------------+ row in set (0.00 sec) mysql> select * from employee where salary > 100000; +----+------+--------+-----+------------+---------+--------------+------------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+------+--------+-----+------------+---------+--------------+------------+--------+-----------+ | 2 | nico | female | 78 | 2015-03-02 | teacher | NULL | 1000000.31 | 401 | 1 | +----+------+--------+-----+------------+---------+--------------+------------+--------+-----------+ 1 row in set (0.00 sec) mysql> select * from emp having salary > 100000; ERROR 1463 (42000): Non-grouping field 'salary' is used in HAVING clause mysql> select post,group_concat(name) from emp group by post having salary > 10000;#错误,分组后无法直接取到salary字段 ERROR 1054 (42S22): Unknown column 'salary' in 'having clause' mysql> select post,group_concat(name) from emp group by post having avg(salary) > 10000; +-----------+---------------------------------------------------------+ | post | group_concat(name) | +-----------+---------------------------------------------------------+ | operation | 程咬铁,程咬铜,程咬银,程咬金,张野 | | teacher | 成龙,jinxin,jingliyang,liwenzhou,jack,anna,nico,alice | +-----------+---------------------------------------------------------+ 2 rows in set (0.00 sec)-------------------------------------------+ rows in set (0.00 sec)
小练习:
1. 查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数 3. 查询各岗位平均薪资大于10000的岗位名、平均工资 4. 查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资
#题1: mysql> select post,group_concat(name),count(id) from employee group by post having count(id) < 2; Empty set (0.00 sec) #题目2: mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000; +-----------+---------------+ | post | avg(salary) | +-----------+---------------+ | operation | 16800.026000 | | teacher | 133775.080000 | +-----------+---------------+ 2 rows in set (0.00 sec) #题目3: mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000; +-----------+--------------+ | post | avg(salary) | +-----------+--------------+ | operation | 16800.026000 | +-----------+--------------+ 1 row in set (0.00 sec)
七 查询排序:ORDER BY
不指定排序,表按照id字段进行排序(升序)
按单列排序 SELECT * FROM employee ORDER BY salary; SELECT * FROM employee ORDER BY salary ASC; 升序(默认) SELECT * FROM employee ORDER BY salary DESC; 降序 按多列排序:先按照age排序,如果年纪相同,则按照薪资排序 SELECT * from employee ORDER BY age, salary DESC;
小练习:
1. 查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序 2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列 3. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列
#题目1 mysql> select * from employee ORDER BY age asc,hire_date desc; +----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+ | 1 | alice | female | 18 | 2017-03-01 | teacher | NULL | 7300.33 | 401 | 1 | | 12 | 星星 | female | 18 | 2016-05-13 | sale | NULL | 3000.29 | 402 | 2 | | 17 | 程咬铜 | male | 18 | 2015-04-11 | operation | NULL | 18000.00 | 403 | 3 | | 18 | 程咬铁 | female | 18 | 2014-05-12 | operation | NULL | 17000.00 | 403 | 3 | | 16 | 程咬银 | female | 18 | 2013-03-11 | operation | NULL | 19000.00 | 403 | 3 | | 11 | 丁丁 | female | 18 | 2011-03-12 | sale | NULL | 1000.37 | 402 | 2 | | 6 | jingliyang | female | 18 | 2011-02-11 | teacher | NULL | 9000.00 | 401 | 1 | | 15 | 程咬金 | male | 18 | 1997-03-12 | operation | NULL | 20000.00 | 403 | 3 | | 7 | jinxin | male | 18 | 1900-03-01 | teacher | NULL | 30000.00 | 401 | 1 | | 13 | 格格 | female | 28 | 2017-01-27 | sale | NULL | 4000.33 | 402 | 2 | | 14 | 张野 | male | 28 | 2016-03-11 | operation | NULL | 10000.13 | 403 | 3 | | 5 | liwenzhou | male | 28 | 2012-11-01 | teacher | NULL | 2100.00 | 401 | 1 | | 10 | 丫丫 | female | 38 | 2010-11-01 | sale | NULL | 2000.35 | 402 | 2 | | 9 | 歪歪 | female | 48 | 2015-03-11 | sale | NULL | 3000.13 | 402 | 2 | | 8 | 成龙 | male | 48 | 2010-11-11 | teacher | NULL | 10000.00 | 401 | 1 | | 4 | jack | male | 73 | 2014-07-01 | teacher | NULL | 3500.00 | 401 | 1 | | 2 | nico | female | 78 | 2015-03-02 | teacher | NULL | 1000000.31 | 401 | 1 | | 3 | anna | female | 81 | 2013-03-05 | teacher | NULL | 8300.00 | 401 | 1 | +----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+ 18 rows in set (0.00 sec) #题目2 mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc; +-----------+---------------+ | post | avg(salary) | +-----------+---------------+ | operation | 16800.026000 | | teacher | 133775.080000 | +-----------+---------------+ 2 rows in set (0.00 sec) #题目3 mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc; +-----------+---------------+ | post | avg(salary) | +-----------+---------------+ | teacher | 133775.080000 | | operation | 16800.026000 | +-----------+---------------+ 2 rows in set (0.00 sec)
八 限制查询的记录数:LIMIT
示例:
SELECT * FROM employee ORDER BY salary DESC
LIMIT 3; #默认初始位置为0
SELECT * FROM employee ORDER BY salary DESC
LIMIT 0,5; #从第0开始,即先查询出第一条,然后包含这一条在内往后查5条
SELECT * FROM employee ORDER BY salary DESC
LIMIT 5,5; #从第5开始,即先查询出第6条,然后包含这一条在内往后查5条
小练习:
1. 分页显示,每页5条
mysql> select * from employee limit 0,5; +----+-----------+--------+-----+------------+---------+--------------+------------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+-----------+--------+-----+------------+---------+--------------+------------+--------+-----------+ | 1 | alice | female | 18 | 2017-03-01 | teacher | NULL | 7300.33 | 401 | 1 | | 2 | nico | female | 78 | 2015-03-02 | teacher | NULL | 1000000.31 | 401 | 1 | | 3 | anna | female | 81 | 2013-03-05 | teacher | NULL | 8300.00 | 401 | 1 | | 4 | jack | male | 73 | 2014-07-01 | teacher | NULL | 3500.00 | 401 | 1 | | 5 | liwenzhou | male | 28 | 2012-11-01 | teacher | NULL | 2100.00 | 401 | 1 | +----+-----------+--------+-----+------------+---------+--------------+------------+--------+-----------+ 5 rows in set (0.00 sec) mysql> select * from employee limit 5,5; +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+ | 6 | jingliyang | female | 18 | 2011-02-11 | teacher | NULL | 9000.00 | 401 | 1 | | 7 | jinxin | male | 18 | 1900-03-01 | teacher | NULL | 30000.00 | 401 | 1 | | 8 | 成龙 | male | 48 | 2010-11-11 | teacher | NULL | 10000.00 | 401 | 1 | | 9 | 歪歪 | female | 48 | 2015-03-11 | sale | NULL | 3000.13 | 402 | 2 | | 10 | 丫丫 | female | 38 | 2010-11-01 | sale | NULL | 2000.35 | 402 | 2 | +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+ 5 rows in set (0.00 sec) mysql> select * from employee limit 10,5; +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+ | id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id | +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+ | 11 | 丁丁 | female | 18 | 2011-03-12 | sale | NULL | 1000.37 | 402 | 2 | | 12 | 星星 | female | 18 | 2016-05-13 | sale | NULL | 3000.29 | 402 | 2 | | 13 | 格格 | female | 28 | 2017-01-27 | sale | NULL | 4000.33 | 402 | 2 | | 14 | 张野 | male | 28 | 2016-03-11 | operation | NULL | 10000.13 | 403 | 3 | | 15 | 程咬金 | male | 18 | 1997-03-12 | operation | NULL | 20000.00 | 403 | 3 | +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
九 使用正则表达式查询
SELECT * FROM employee WHERE name REGEXP '^al'; # 开头 SELECT * FROM employee WHERE name REGEXP 'on$'; # 结尾 SELECT * FROM employee WHERE name REGEXP 'm{2}'; 小结:对字符串匹配的方式 WHERE name = 'egon'; WHERE name LIKE 'yua%'; WHERE name REGEXP 'on$';
小练习:
查看所有员工中名字是jin开头,n或者g结果的员工信息
select * from employee where name regexp '^jin.*(g|n)$';