• HDU 1754 I Hate It (线段树)


    题意:略。

    析:裸的线段树。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <cmath>
    #include <stack>
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define freopenr freopen("in.txt", "r", stdin)
    #define freopenw freopen("out.txt", "w", stdout)
    using namespace std;
    
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int maxn = 200000 + 5;
    const int mod = 1e9 + 7;
    const int dr[] = {0, 1, 0, -1, -1, 1, 1, -1};
    const int dc[] = {1, 0, -1, 0, 1, 1, -1, -1};
    const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
    int n, m;
    const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    inline int Min(int a, int b){ return a < b ? a : b; }
    inline int Max(int a, int b){ return a > b ? a : b; }
    inline LL Min(LL a, LL b){ return a < b ? a : b; }
    inline LL Max(LL a, LL b){ return a > b ? a : b; }
    inline bool is_in(int r, int c){
        return r >= 0 && r < n && c >= 0 && c < m;
    }
    int maxv[maxn<<2];
    
    void pushup(int rt){ maxv[rt] = Max(maxv[rt<<1], maxv[rt<<1|1]); }
    
    void build(int l, int r, int rt){
        if(l == r){
            scanf("%d", &maxv[rt]);
            return ;
        }
        int m = (l + r) >> 1;
        build(lson);
        build(rson);
        pushup(rt);
    }
    
    void update(int x, int val, int l, int r, int rt){
        if(l == r){
            maxv[rt] = val;
            return ;
        }
        int m = (l + r) >> 1;
        if(x <= m)  update(x, val, lson);
        if(x > m)   update(x, val, rson);
        pushup(rt);
    }
    
    int query(int L, int R, int l, int r, int rt){
        if(L <= l && r <= R)  return maxv[rt];
        int m = (l + r) >> 1;
        int ans = -INF;
        if(L <= m)  ans = Max(ans, query(L, R, lson));
        if(R > m)   ans = Max(ans, query(L, R, rson));
        return ans;
    }
    
    int main(){
        while(scanf("%d %d", &n, &m) == 2){
            build(1, n, 1);
            char s[5];
            int x, y;
            while(m--){
                scanf("%s", s);
                if(s[0] == 'Q'){
                    scanf("%d %d", &x, &y);
                    printf("%d
    ", query(x, y, 1, n, 1));
                }
                else{
                    scanf("%d %d", &x, &y);
                    update(x, y, 1, n, 1);
                }
            }
        }
        return 0;
    }
    
  • 相关阅读:
    R语言实战
    Python Google Translate API
    Windows使用技巧
    test_CSDN_markdown_format
    Linux: bash script
    test_markdown
    线性基学习笔记+模板总结
    Educational Codeforces Round 69 D Yet Another Subarray Problem
    图片托管
    二维线段树模板,建树,维护最大最小值
  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/6080943.html
Copyright © 2020-2023  润新知