JavaScript 中 new Date() 时间使用

JavaScript 中 new Date() 时间使用

01)JavaScript获取当前时间加上10分钟

遇到整点可以累加到下一时间

  // JavaScript获取当前时间加上10分钟
  function dateAdd(dStr, interval = 10) {
    let d = new Date(
        dStr.substring(0, 4),
        dStr.substring(5, 7) - 1,
        dStr.substring(8, 10),
        dStr.substring(11, 13),
        dStr.substring(14, 16),
        dStr.substring(17, 19)
    );
    d.setTime(d.getTime() + interval * 60 * 1000);
    //小于10前面补0
    let getMonth = (d.getMonth() + 1) < 10 ? "0" + (d.getMonth() + 1) : d.getMonth() + 1;
    let getDate = d.getDate() < 10 ? "0" + (d.getDate()) : d.getDate();
    let getHours = d.getHours() < 10 ? "0" + (d.getHours()) : d.getHours();
    let getMinutes = d.getMinutes() < 10 ? "0" + (d.getMinutes()) : d.getMinutes();
    return d.getFullYear() + "-" + getMonth + "-" + getDate + " " + getHours + ":" + getMinutes;
  }
  console.log(dateAdd('2022-02-20 08:00'))

02)JavaScript获取当前时间减去10分钟

遇到整点可以累加到下一时间

  // JavaScript获取当前时间减去10分钟
  function dateDecrease(dStr,interval = 10) {
    let d = new Date(
        dStr.substring(0, 4),
        dStr.substring(5, 7) - 1,
        dStr.substring(8, 10),
        dStr.substring(11, 13),
        dStr.substring(14, 16),
        dStr.substring(17, 19)
    );
    d.setTime(d.getTime() - interval * 60 * 1000);
    //小于10前面补0
    let getMonth = (d.getMonth() + 1) < 10 ? "0" + (d.getMonth() + 1) : d.getMonth() + 1;
    let getDate = d.getDate() < 10 ? "0" + (d.getDate()) : d.getDate();
    let getHours = d.getHours() < 10 ? "0" + (d.getHours()) : d.getHours();
    let getMinutes = d.getMinutes() < 10 ? "0" + (d.getMinutes()) : d.getMinutes();
    return d.getFullYear() + "-" + getMonth + "-" + getDate + " " + getHours + ":" + getMinutes;
  }
  console.log(dateDecrease('2022-02-04 08:00'))