• UVALive 3634 熟悉一下STL


    Given this imp ortance of sets, b eing the basis of mathematics, a set of eccentric theorist set off to
    construct a sup ercomputer op erating on sets instead of numb ers. The initial SetStack Alpha is under construction, and they need you to simulate it in order to verify the op eration of the prototyp e.
    The computer op erates on a single stack of sets, which is initially empty. After each op eration, the
    cardinality of the topmost set on the stack is output. The cardinality of a set S is denoted | S | and is the number of elements in S. The instruction set of the SetStack Alpha is PUSH, DUP, UNION, INTERSECT,and ADD.
    PUSH will push the empty set {} on the stack.
    DUP will duplicate the topmost set (pop the stack, and then push that set on the stack twice).
    UNION will pop the stack twice and then push the union of the two sets on the stack.
    INTERSECT will pop the stack twice and then push the intersection of the two sets on the stack.
    ADD will pop the stack twice, add the first set to the second one, and then push the resulting set on the stack.
    For illustration purposes, assume that the topmost element of the stack is
    A = {{} , {{}}}
    and that the next one is
    B = {{} , {{{}}}}
    For these sets, we have | A | = 2 and | B | = 2. Then:
    UNION would result in the set {{}, {{}}, {{{}}}}. The output is 3.
    INTERSECT would result in the set {{}}. The output is 1.
    ADD would result in the set {{}, {{{}}}, {{}, {{}}}}. The output is 3.
    Input
    An integer 0 ≤ T ≤ 5 on the first line gives the cardinality of the set of test cases. The first line of each test case contains the number of operations 0 ≤ N ≤ 2000. Then follow N lines each containing one of the five commands. It is guaranteed that the SetStack computer can execute all the commands in the sequence without ever popping an empty stack.
    Output
    For each operation specified in the input, there will be one line of output consisting of a single integer.This integer is the cardinality of the topmost element of the stack after the corresponding command has executed. After each test case there will be a line with ‘ *’ (three asterisks).
    Sample Input
    29
    PUSH
    DUP
    ADD
    PUSH
    ADD
    DUP
    ADD
    DUP
    UNION
    5
    PUSH
    PUSH
    ADD
    PUSH
    INTERSECT
    Given this imp ortance of sets, b eing the basis of mathematics, a set of eccentric theorist set off to
    construct a sup ercomputer op erating on sets instead of numb ers. The initial SetStack Alpha is under
    construction, and they need you to simulate it in order to verify the op eration of the prototyp e.
    The computer op erates on a single stack of sets, which is initially empty. After each op eration, the
    cardinality of the topmost set on the stack is output. The cardinality of a set S is denoted | S | and is the
    number of elements in S. The instruction set of the SetStack Alpha is PUSH, DUP, UNION, INTERSECT,
    and ADD.
    • PUSH will push the empty set {} on the stack.
    • DUP will duplicate the topmost set (pop the stack, and then push that set on the stack twice).
    • UNION will pop the stack twice and then push the union of the two sets on the stack.
    • INTERSECT will pop the stack twice and then push the intersection of the two sets on the stack.
    • ADD will pop the stack twice, add the first set to the second one, and then push the resulting set
    on the stack.
    For illustration purposes, assume that the topmost element of the stack is
    A = {{} , {{}}}
    and that the next one is
    B = {{} , {{{}}}}
    For these sets, we have | A | = 2 and | B | = 2. Then:
    • UNION would result in the set {{}, {{}}, {{{}}}}. The output is 3.
    • INTERSECT would result in the set {{}}. The output is 1.
    • ADD would result in the set {{}, {{{}}}, {{}, {{}}}}. The output is 3.
    Input
    An integer 0 ≤ T ≤ 5 on the first line gives the cardinality of the set of test cases. The first line of each
    test case contains the number of operations 0 ≤ N ≤ 2000. Then follow N lines each containing one of
    the five commands. It is guaranteed that the SetStack computer can execute all the commands in the
    sequence without ever popping an empty stack.
    Output
    For each operation specified in the input, there will be one line of output consisting of a single integer.
    This integer is the cardinality of the topmost element of the stack after the corresponding command
    has executed. After each test case there will be a line with ‘ *’ (three asterisks).
    Sample Input
    29
    PUSH
    DUP
    ADD
    PUSH
    ADD
    DUP
    ADD
    DUP
    UNION
    5
    PUSH
    PUSH
    ADD
    PUSH
    INTERSECT
    Sample Output
    0
    1
    0
    1
    2


    010


    直接用集合和栈操作,

    #include<iostream>
    #include<set>
    #include<stack>
    #include<cstdio>
    #include<map>
    using namespace std;
    int cnt;
    char st[20];
    set<int>s1,s2;
    stack<set<int> >s;
    map<set<int>,int >mp;
    
    void POP(){s1=s.top();s.pop();s2=s.top();s.pop();}
    void PUSH(){set<int>t;s.push(t);puts("0");}
    void DUP(){s.push(s.top());printf("%d
    ",s.top().size());}
    
    void UNION(){
        POP();
        for (set<int>::iterator i=s1.begin();i!=s1.end();i++) 
            s2.insert(*i);
        s.push(s2);
        printf("%d
    ",s.top().size());
    }
    
    void INTERSECT(){
        POP();  set<int>s3;
        for (set<int>::iterator i=s1.begin();i!=s1.end();i++)
            if (s2.find(*i)!=s2.end())s3.insert(*i);
        s.push(s3);
        printf("%d
    ",s.top().size());
    }
    
    void ADD(){
        POP();
        if (s1.empty())s2.insert(0);
        else{
            if (!mp[s1])mp[s1]=cnt++;
            s2.insert(mp[s1]);
        }
        s.push(s2);
        printf("%d
    ",s.top().size());
    }
    
    int main(){
        freopen("fuck.in","r",stdin);
        int T;scanf("%d",&T);
        while (T--){
            cnt=1;
            int n;scanf("%d",&n);
            while(!s.empty())s.pop();
            mp.clear();
            for (int i=0;i<n;i++){
                scanf("%s",st);
                if (st[0]=='P') PUSH();
                if (st[0]=='D') DUP();
                if (st[0]=='U') UNION();
                if (st[0]=='I') INTERSECT();
                if (st[0]=='A') ADD();
            }
            puts("***");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/cww97/p/7534036.html
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