• 预科班D9


    2020.09.17星期四  预科班D9

    学习内容:

    一、列表与字典的嵌套

    大前提:将所有同学的信息存起来,取值需求

    1、取第二个学生的性别

    stus_info = [

      {"name": "uzi", "age": 18, "gender": "male"},

      {"name": "lili", "age": 20, "gender": "female"},

      {"name": "jack", "age": 25, "gender": "male"},

    ]   

    print(stus_info[1]["gender"])

    2、取uzi的年龄

    stus_info ={

      "uzi": {"age": 18, "gender": "male"},

      "lili": {"age": 20, "gender": "female"},

      "jack": {"age": 25, "gender": "male"},

    }  

    print(stus_info["uzi"]["age"])

    3、取uzi多个爱好中的第一个

    stus_info = {
    "lili": {"age": 18, "gender": "female", "hobbies": ["play", "read"]},
    "uzi": {"age": 19, "gender": "male", "hobbies": ["music", "play", "read"]},
    }
    print(stus_info["uzi"]["hobbies"][0])

    二、输入输出

    1、输入

    db_user = "drug"
    inp_user = input("请输入你的用户名:")
    print(inp_user == db_user)  # 输入为drug则True,否则False.

     2、输出

    print("My name is %s My age is %s"  %("Drug","28"))
    #输出为My name is Drug My age is 28
    #%s内容可换

    TIPS: print("hello")

              print("world")中自带换行,应是print("world",end="/n")

    三、基本运算符

    1、算数运算符

    print(10 - 3.1)  # 减法
    print(10 + 3.1)  # 加法
    print(10 * 3.1)  # 乘法
    print(10 / 3)  # 除法
    print(10 // 3)  # 只保留整数部分
    print(10 % 3)  # 取余数,取模
    print(10 ** 3)  # 10的3次方

    2、赋值运算符

    age = 18
    age += 3  # age = age + 3
    age *= 3  # age = age * 3
    age /= 3  # age = age / 3
    age **= 3  # age = age **               

    3、比较运算符

    print(10 > 3)  # True
    print(10 >= 3)  # True
    print(10 < 3)  # False
    print(10 <= 3)  # False
    print(10 == 10.0)  # True
    print("drug" == "drug")  # True
    print([1,2,3] == [2,3,1])  # False
    print([1,2,3] == [1,2,3])  # True
    print(10 != 3)  # True10不等于3

    4、逻辑运算符

    #not
    print(10 > 3)  # True
    print(not 10 > 3)  # False
    
    #and
    print(10 > 3 and True and 3 == 10)  # False
    print(10 > 3 and False and 3 == 10)  # False
    
    #or
    print(10 < 3 or 3 > 100 or 3 == 10)  # True
    print(10 > 3 or 3 > 100 or 3 != 10)  # True
    
    #短路运算
    #and运算中从前到后只要有一个不成立,后面不用看了直接False
    #or运算中从前到后只要有一个成立,后面不用看了直接True

    5、流程控制之if判断

    if 条件1:

      代码1

      代码2

      代码3

      ...

    elif 条件2:

      代码1

      代码2

      代码3

      ...

    elif 条件3:

      代码1

      代码2

      代码3

      ...

    ......

    else:

      代码1

      代码2

      代码3

      ...

    1、单分支

    gender = "female"
    age = 18
    is_beautiful=True
    
    if gender == "female" and age > 16 and age < 20 and is_beautiful:
        print("NICE冲冲冲!!!")
    
    print('HAVE A NICE DAY!')

    2、双分支

    gender = "female"
    age = 21
    is_beautiful=True
    
    if gender == "female" and age > 16 and age < 20 and is_beautiful:
        print("NICE冲冲冲!!!")
    else:
        print("886")
    
    print('HAVE A NICE DAY!')

    3、if嵌套

    gender = "female"
    age = 19
    is_beautiful=True
    is_ok=True
    
    if gender == "female" and age > 16 and age < 20 and is_beautiful:
        print("NICE冲冲冲!!!")
        if is_ok:
            print("NICE")
        else:
            print("886")
    else:
        print("886")
        
    print('HAVE A NICE DAY!')

    4、例子

    码农------------------------------计算机
    接收用户输入的账号
    接收用户输入的密码
    判断 输入的账号 等于 正确的账号 并且 输入的密码 等于 正确的密码:
    告诉用户登录成功
    否则:
    告诉用户账号或密码输入错误
    inp_user = input("请输入您的账号:")
    inp_pwd = input("请输入您的密码:")  # inp_pwd = "123"
    
    if inp_user == "egon" and inp_pwd == "123":
        print("登录成功")
    else:
        print("用户账号或密码输入错误")
  • 相关阅读:
    终于合一起了...
    关于Earley第二篇论文给的建立parse tree的算法的bug
    不作恶
    windows server安装ATI显卡驱动
    不作恶:这次我是一个坚定的五毛党
    看了老刘的文章
    webkit svg高斯模糊的bug
    世界不平坦
    我发现我对人类活动的认识开始有一点点变化了
    css parsing中词法的RegEx(python)
  • 原文地址:https://www.cnblogs.com/caojiaxin/p/13687524.html
Copyright © 2020-2023  润新知