• Swift


    一、数组 - Array

    var types = ["none","warning","error"]//省略类型的数组声明
        var menbers = [String]()//声明一个空数组
            
        menbers.append("six") //添加元素
        menbers += ["seven"] //添加元素
        menbers.insert("one", at: 0)//指定位置添加元素
            
        menbers[0] = "message" //通过下标修改数组中的数据
        menbers[0...2] = ["message","hangge","com"] //通过小标区间替换数据(前3个数据)
        menbers.count // 获取数组元素个数
        menbers.isEmpty //判断数组是否为空
        
        //交换元素位置(第2个和第3个元素位置进行交换)
        menbers.swapAt(1, 2)
            
        menbers.remove(at: 2)//删除下标为2的数组
        menbers.removeLast()//删除最后一个元素
        menbers.removeAll(keepingCapacity: true)//删除数组中所有元素
            
        let addStringArr = types + menbers//数组组合
        //使用for in 实现数组遍历
            for value in menbers{
                print("(value)")
            }
           
        //通过enumerate函数同时遍历数组的所有索引与数据
            for(index,value) in menbers.enumerated(){
                print("索引:(index) 数据:(value)");
            }
            //过滤数组元素
        let newTypes = types.filter { $0.count < 6 } //["none", "error"]
    

    二、字典 - Dictionary(即键值对)

      var empty = [String:Int]() //建立个空字典
            
            var myDic = ["name":"hangge","url":"hangge.com"]//声明一个字典
            myDic["address"] = "china"//添加或修改key值
            myDic.removeValue(forKey: "name")//删除“name”这个key值
            myDic["name"] = nil //同样可以删除“name”这个key值
            myDic.keys  //访问字典的key集合
    //        print(myDic.values) //访问字典的values集合
            
            //遍历字典
            for(key,value) in myDic{
                print("(key):(value)");
            }
            
            //只遍历字典的键(key)
            for key in myDic.keys{
                print("(key)");
            }
            //只遍历字典的值(value)
            for value in myDic.values{
                print("(value)");
            }
    

    2,其它几种创建字典的方法

    (1)通过元组创建字典

    let tupleArray = [("Monday",30),("Tuesday",25),("Wednesday",27)]
            let dictionary = Dictionary(uniqueKeysWithValues: tupleArray)
            print(dictionary)
    

     (2)通过键值序列创建字典

    let names = ["Apple", "Pear"]
            let prices = [7, 6]
            let dict = Dictionary(uniqueKeysWithValues: zip(names, prices))
            print(dict);
    

     (3)只有键序列、或者值序列创建字典

    let array = ["Monday","Tuesday","Wednesday"]
            let dict1 = Dictionary(uniqueKeysWithValues:zip(1..., array))
            let dict2 = Dictionary(uniqueKeysWithValues:zip(array, 1...))
            print("dict1:(dict1)")
            print("dict2:(dict2)")
    

    (4)字典分组(比如下面生成一个以首字母分组的字典)

        let names = ["Apple","Pear","Grape","Peach"]
            let dict = Dictionary(grouping:names){ $0.first!}
            print(dict)
    

    3,重复键的处理

    (1)zip配合速记+可以用来解决重复键的问题(相同的键值相加)

     let array = ["Apple","Pear","Pear","Orange"]
        let dic = Dictionary(zip(array, repeatElement(1, count: array.count)),uniquingKeysWith: +)
        print(dic)
    

     (2)下面使用元组创建字典时,遇到相同的键则取较小的那个值

     let duplicatesArray = [("Monday",30),("Tuesday",25),("Wednesday",27),("Monday",28)]
            let dic = Dictionary(duplicatesArray, uniquingKeysWith:min)
            print(dic) // ["Monday": 28, "Tuesday": 25, "Wednesday": 27]
    

    4,字典合并

    想要将一些序列、或者字典合并到现有的字典中,可以借助如下两个合并方法:

    • merge(_: uniquingKeysWith:):这种方法会修改原始Dictionary
    • merging(_: uniquingKeysWith:):这种方法会创建并返回一个全新的Dictionary
    var dic = ["one":10,"two":20]
            //merge方法合并
            let tuples = [("one",5), ("three",30)]
            dic.merge(tuples, uniquingKeysWith: min)
            print(dic);//["one": 5, "three": 30, "two": 20]
            
            //merging 方法合并
            let dic2 = ["one":0,"four":40]
            let dic3 = dic.merging(dic2, uniquingKeysWith: min)
            print(dic3)//["three": 30, "four": 40, "one": 0, "two": 20]
    

    5,默认值

    (1)过去我们如果希望当某个字典值不否存在时,使用一个指定的默认值,这个通常会使用if let来判断实现。

      let dic = ["apple":1,"banana":2]
            var orange:Int
            if let value = dic["orange"]{
                orange = value
            }else{
                orange = 0
            }
            print(orange)//打印0
    

    (2)到了 Swift4,我们可以直接指定一个默认值,如果不存在该键值时名,会直接返回这个值。下面代码的效果同上面是一样的。

    let dic = ["aaple":1,"banana":2]
            let orange = dic["orange", default:0]
            print(orange)//打印0

     (3)下面是统计一个字符串中所有单词出现的次数。可以看到了有了默认值,实现起来会简单许多。

     let str = "apple banana orange apple banana"
            var wordsCount: [String: Int] = [:]
            for word in str.split(separator:" "){
                wordsCount["(word)", default:0] += 1
            }
            print(wordsCount)//["apple": 2, "orange": 1, "banana": 2]
    

    三、结构体 - struct

    struct BookInfo {
        var ID:Int = 0
        var Name:String = "Defaut"
        var Author:String = "Defaut"
    }
    
    
    var book1:BookInfo//默认构造器创建结构体实现
            var book2 = BookInfo(ID: 0021, Name: "白白", Author: "baibai")//调用逐一构造器创建实列
            book2.ID = 1234 //修改内部值
    

    四、枚举 - enum

    enum CompassPoint{
        case north
        case south
        case east
        case west
    }
    enum Planet:Int{
        case mercury = 1
        case venus = 2
        case earth = 3
    }
    
    enum Direction{
        case up
        case down
        
        func description() -> String {
            switch self {
            case .up:
                return "向上"
            case .down:
                return "向下"
            }
        }
    }
    
    
     var dirctionToHead = CompassPoint.west
            let earthsOrder = Planet.earth.rawValue //rawValue来获取他的原始值:3
            let possiblePlanet = Planet(rawValue: 2)  //通过原始值来寻找所对应的枚举成员:Venus
            
            print(dirctionToHead)
            print(earthsOrder)
            print(possiblePlanet)
            
            print(Direction.up.description())
    
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  • 原文地址:https://www.cnblogs.com/baidaye/p/8575381.html
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