Given an input string, reverse the string word by word.
For example,
Given s = "the sky is blue
",
return "blue is sky the
".
Clarification:
- What constitutes a word?
A sequence of non-space characters constitutes a word. - Could the input string contain leading or trailing spaces?
Yes. However, your reversed string should not contain leading or trailing spaces. - How about multiple spaces between two words?
Reduce them to a single space in the reversed string.
思路:从头往后扫描字符串,从第一个开始不是空格算起。将单词放入temp中,直到遇到空格,作如下处理,将单词放入result中去,接下来再有单词可以放到上一个单词的前面,另加空格。如此反复,就可以将单词与单词为单位反转了。
class Solution { public: void reverseWords(string &s) { int nLen=s.size(); if(nLen<=0) return; string temp,result; int index=0; while(s[index]==' ') index++; for(int i=index;i<nLen;) { if(s[i]!=' ') { temp+=s[i]; i++; } else { while(s[i]==' ') i++; if(i==nLen) break; result=" "+temp+result; temp=""; } } s=temp+result; } };