• bzoj 1208 宠物收养所--splay


    这个题也是单点维护,不管来的是人还是狗,只要num=0就插入,否则就删除。

    // File Name: ACM/bzoj/1208.cpp
    // Author: Zlbing
    // Created Time: 2013年08月08日 星期四 16时33分53秒
    
    #include<iostream>
    #include<string>
    #include<algorithm>
    #include<cstdlib>
    #include<cstdio>
    #include<set>
    #include<map>
    #include<vector>
    #include<cstring>
    #include<stack>
    #include<cmath>
    #include<queue>
    using namespace std;
    #define CL(x,v); memset(x,v,sizeof(x));
    #define INF 0x3f3f3f3f
    #define LL long long
    #define REP(i,r,n) for(int i=r;i<=n;i++)
    #define RREP(i,n,r) for(int i=n;i>=r;i--)
    const int MAXN=8e4+100;
    const int mod=1000000;
    struct SplayTree {  
        int sz[MAXN];  
        int ch[MAXN][2];  
        int pre[MAXN];  
        int rt,top;  
        inline void up(int x){  
            sz[x]  = cnt[x]  + sz[ ch[x][0] ] + sz[ ch[x][1] ];  
        }  
        inline void Rotate(int x,int f){  
            int y=pre[x];  
            ch[y][!f] = ch[x][f];  
            pre[ ch[x][f] ] = y;  
            pre[x] = pre[y];  
            if(pre[x]) ch[ pre[y] ][ ch[pre[y]][1] == y ] =x;  
            ch[x][f] = y;  
            pre[y] = x;  
            up(y);  
        }  
        inline void Splay(int x,int goal){//将x旋转到goal的下面  
            while(pre[x] != goal){  
                if(pre[pre[x]] == goal) Rotate(x , ch[pre[x]][0] == x);  
                else   {  
                    int y=pre[x],z=pre[y];  
                    int f = (ch[z][0]==y);  
                    if(ch[y][f] == x) Rotate(x,!f),Rotate(x,f);  
                    else Rotate(y,f),Rotate(x,f);  
                }  
            }  
            up(x);  
            if(goal==0) rt=x;  
        }  
        inline void RTO(int k,int goal){//将第k位数旋转到goal的下面  
            int x=rt;  
            while(sz[ ch[x][0] ] != k-1) {  
                if(k < sz[ ch[x][0] ]+1) x=ch[x][0];  
                else {  
                    k-=(sz[ ch[x][0] ]+1);  
                    x = ch[x][1];  
                }  
            }  
            Splay(x,goal);  
        }  
        inline void vist(int x){  
            if(x){  
                printf("结点%2d : 左儿子  %2d   右儿子  %2d   %2d sz=%d
    ",x,ch[x][0],ch[x][1],val[x],sz[x]);  
                vist(ch[x][0]);  
                vist(ch[x][1]);  
            }  
        }  
        inline void Newnode(int &x,int c){  
            x=++top;  
            ch[x][0] = ch[x][1] = pre[x] = 0;  
            sz[x]=1; cnt[x]=1;  
            val[x] = c;  
        }  
        inline void init(){  
            ans=0;type=-1;  
            ch[0][0]=ch[0][1]=pre[0]=sz[0]=0;  
            rt=top=0; cnt[0]=0;  
            Newnode(rt,-INF);  
            Newnode(ch[rt][1],INF);  
            pre[top]=rt;  
            sz[rt]=2;  
        }  
        inline void Insert(int &x,int key,int f){  
            if(!x) {  
                Newnode(x,key);  
                pre[x]=f;  
                Splay(x,0);  
                return ;  
            }  
            if(key==val[x]){  
                cnt[x]++;  
                sz[x]++;  
                return ;  
            }else if(key<val[x]) {  
                Insert(ch[x][0],key,x);  
            } else {  
                Insert(ch[x][1],key,x);  
            }  
            up(x);  
        }  
    void Del(){ //删除根结点
          int t=rt; if(ch[rt][1]) { rt=ch[rt][1]; RTO(1,0); ch[rt][0]=ch[t][0]; if(ch[rt][0]) pre[ch[rt][0]]=rt; } else rt=ch[rt][0]; pre[rt]=0; up(rt); } void findpre(int x,int key,int &ans){ //找key前趋 if(!x) return ; if(val[x] <= key){ ans=x; findpre(ch[x][1],key,ans); } else findpre(ch[x][0],key,ans); } void findsucc(int x,int key,int &ans){ //找key后继 if(!x) return ; if(val[x]>=key) { ans=x; findsucc(ch[x][0],key,ans); } else findsucc(ch[x][1],key,ans); } int cnt[MAXN]; int val[MAXN]; int type; int ans; }spt; int main() { int n; while(~scanf("%d",&n)) { spt.init(); int a,b; int ans=0; int type=-1; REP(i,1,n) { scanf("%d%d",&a,&b); if(a==type||spt.sz[spt.rt]==2) { spt.Insert(spt.rt,b,0); type=a; //spt.vist(spt.rt); } else { int x,y; if(spt.sz[spt.rt]==2)continue; spt.findpre(spt.rt,b,x); spt.findsucc(spt.rt,b,y); if(abs(spt.val[x]-b)<=abs(spt.val[y]-b)) { ans+=abs(spt.val[x]-b); ans%=mod; spt.Splay(x,0); //spt.vist(spt.rt); spt.Del(); } else{ ans+=abs(spt.val[y]-b); ans%=mod; spt.Splay(y,0); //spt.vist(spt.rt); spt.Del(); } } } printf("%d ",ans); } return 0; }
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  • 原文地址:https://www.cnblogs.com/arbitrary/p/3249777.html
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