• CCF-CSP题解 201912-3 化学方程式


    判断化学方程式是否配平。

    字符串处理。

    有点编译原理递归下降法的感觉。

    考场源码,比较粗糙。

    // INFO BEGIN
    //
    // User = 201911513451(陶杨) 
    // Group = C/C++ 
    // Problem = 化学方程式 
    // Language = CPP11 
    // SubmitTime = 2019-12-15 16:20:32 
    //
    // INFO END
    
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    
    char str[1005];
    
    int nums[27][27];
    
    void elementSingle(int l, int r, int left, int coef, int coef2) {
        if (l > r) return;
        int e1, e2 = 0;
        e1 = str[l] - 'A' + 1;  // [1,26]
        if (l < r && !(str[l + 1] >= '0' && str[l + 1] <= '9')) e2 = str[l + 1] - 'a' + 1;
        int mid = l + 1;
        if (e2 != 0) ++mid;
        int co = 0;
        while (mid <= r) co = co * 10 + str[mid++] - '0';
        if (co == 0) co = 1;
        nums[e1][e2] += left * coef * coef2 * co;
    }
    
    void element(int l, int r, int left, int coef, int coef2) {
        if (l > r) return;
        // printf("%d %d %d ", left, coef, coef2);
        // for (int i = l; i <= r; ++i) printf("%c", str[i]); printf("
    ");
        int mid = l + 1;
        for (; mid <= r && !(str[mid] >= 'A' && str[mid] <= 'Z'); ++mid);
        if (mid <= r) {
            elementSingle(l, mid - 1, left, coef, coef2);
            element(mid, r, left, coef, coef2);
        } else elementSingle(l, r, left, coef, coef2);
    }
    
    void formula(int l, int r, int left, int coef, int coef2) {
        if (l > r) return;
        int lb = -1, rb = -1, lmore = 0;
        for (int i = l; i <= r; ++i) {
            if (str[i] == '(') {
                ++lmore;
                if (lb == -1) lb = i;
            }
            if (str[i] == ')') {
                --lmore;
                if (lmore == 0 && rb == -1) rb = i;
            }
            if (rb != -1) break;
        }
        if (rb == -1) element(l, r, left, coef, coef2); else {
            int co = 0, mid = rb + 1;
            for (; mid <= r && str[mid] >= '0' && str[mid] <= '9'; ++mid) co = co * 10 + str[mid] - '0';
            if (co == 0) co = 1;
            element(l, lb - 1, left, coef, coef2);
            formula(lb + 1, rb - 1, left, coef, coef2 * co);
            formula(mid, r, left, coef, coef2);
        }
    }
    
    void exprSingle(int l, int r, int left) {
        if (l > r) return;
        int coef = 0, mid = l;
        for (; mid <= r && str[mid] >= '0' && str[mid] <= '9'; ++mid) coef = coef * 10 + str[mid] - '0';
        if (coef == 0) coef = 1;
        formula(mid, r, left, coef, 1);
    }
    
    void expr(int l, int r, int left) {
        if (l > r) return;
        int mid = l;
        for (; mid <= r && str[mid] != '+'; ++mid);
        if (mid <= r) {
            exprSingle(l, mid - 1, left);
            expr(mid + 1, r, left);
        } else exprSingle(l, r, left);
    }
    
    // [l,r]
    void equation(int l, int r) {
        if (l > r) return;
        int mid = l;
        for (; str[mid] != '='; ++mid);
        expr(l, mid - 1, 1);
        expr(mid + 1, r, -1);
    }
    
    int main() {
        int n;
        scanf("%d", &n);
        for (int _ = 0; _ < n; ++_) {
            scanf("%s", str);
            memset(nums, 0, sizeof(nums));
            equation(0, strlen(str) - 1);
            bool flag = true;
            for (int i = 1; i <= 26; ++i) {
                for (int j = 0; j <= 26; ++j) {
                    if (nums[i][j] != 0)
                        flag = false;
                }
            }
            if (flag) printf("Y
    ");
            else printf("N
    ");
        }
        return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/acboyty/p/12074604.html
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