• Codeforces Round #573 (Div. 2).A


    A - Tokitsukaze and Enhancement

    题目链接:http://codeforces.com/contest/1191/problem/A

    题目:

    Tokitsukaze is one of the characters in the game "Kantai Collection". In this game, every character has a common attribute — health points, shortened to HP.

    In general, different values of HP are grouped into 4 categories:   Category A

    if HP is in the form of (4n+1), that is, when divided by 4, the remainder is 1;
    Category B
    if HP is in the form of (4n+3), that is, when divided by 4, the remainder is 3;
    Category C
    if HP is in the form of (4n+2), that is, when divided by 4, the remainder is 2;
    Category D
    if HP is in the form of 4n, that is, when divided by 4, the remainder is 0

    The above-mentioned n can be any integer.

    These 4
    categories ordered from highest to lowest as A>B>C>D, which means category A is the highest and category D is the lowest.

    While playing the game, players can increase the HP of the character. Now, Tokitsukaze wants you to increase her HP by at most 2
    (that is, either by 0, 1 or 2). How much should she increase her HP so that it has the highest possible category?
    Input

    The only line contains a single integer x
    (30≤x≤100) — the value Tokitsukaze's HP currently.
    Output

    Print an integer a(0≤a≤2) and an uppercase letter b (b∈{A,B,C,D}), representing that the best way is to increase her HP by a, and then the category becomes b
    Note that the output characters are case-sensitive.
    Examples
    Input
    33
    Output
    0 A
    Input
    98
    Output
    1 B
    Note

    For the first example, the category of Tokitsukaze's HP is already A, so you don't need to enhance her ability.
    For the second example:
     If you don't increase her HP, its value is still 98, which equals to (4×24+2), and its category is C.
    If you increase her HP by 1, its value becomes 99, which equals to (4×24+3), and its category becomes B.
    If you increase her HP by 2, its value becomes 100, which equals to (4×25), and its category becomes D .
    Therefore, the best way is to increase her HP by 1
    so that the category of her HP becomes B.

    题意:

    Tokitsukaze是游戏“Kantai Collection”中的角色之一。在这个游戏中,每个角色都有一个共同的属性 - 健康点,缩短为HP。

    通常,不同的HP值分为4类:A类

    如果HP是(4n + 1)的形式,也就是说,当除以4时,余数为1;
    B类
    如果HP的形式为(4n + 3),即除以4,则余数为3;
    C类
    如果HP的形式为(4n + 2),即除以4,则余数为2;
    D类
    如果HP是4n的形式,也就是说,当除以4时,余数为0

    上述n可以是任何整数。

    这4个
    从A到B> C> D从最高到最低排序的类别,这意味着A类最高,D类最低。

    在玩游戏时,玩家可以增加角色的HP。现在,Tokitsukaze希望你将她的HP增加至多2
    (即0,1或2)。她应该增加多少HP以使其具有最高级别?
    输入

    唯一的行包含一个整数x
    (30≤x≤100) - 目前Tokitsukaze的HP值。
    产量

    打印一个整数a(0≤a≤2)和一个大写字母b(b∈{A,B,C,D}),表示最好的方法是将她的HP增加a,然后该类别变为b
    请注意,输出字符区分大小写。
    例子
    输入
    33
    产量
    0 A.
    输入
    98
    产量
    1 B
    注意

    对于第一个例子,Tokitsukaze的HP类别已经是A,所以你不需要增强她的能力。
    对于第二个例子:
     如果你不增加她的HP,它的值仍然是98,等于(4×24 + 2),其类别是C.
    如果将HP增加1,则其值变为99,等于(4×24 + 3),其类别变为B.
    如果将HP增加2,则其值变为100,等于(4×25),其类别变为D.
    因此,最好的方法是将她的HP增加1
    这样她的HP类别就变成了B.

    思路:模拟即可

    #include<iostream>
    #include<queue>
    #include<cstring>
    #include<cstdio>
    using namespace std;
    
    const int maxn=2e5+7;
    
    int main()
    {
        int n;
        while(cin>>n) {
            if(n%4==1)
                printf("0 A
    ");
            else if(n%4==2)
                printf("1 B
    ");
            else if(n%4==3)
                printf("2 A
    ");
            else
                printf("1 A
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Vampire6/p/11194007.html
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