C++ 重载中括号

1 中括号重载.cpp

#include<iostream>
#include<string.h>
using namespace std;

class my_string{
    char* p=nullptr;
    public:
    my_string(){}
    my_string(const char* s){
        if(s){
            p = new char[strlen(s)+1];
            strcpy(p,s);
        }
    }
    my_string( const my_string& ms){
        if(ms.p){
            if(p)delete []p;
            p = new char[ms.size()+1];
            strcpy(p,ms.p);
        }
    }
    ~my_string(){
        if(p)delete [] p;
    }
friend ostream &operator<<(ostream&cout,my_string &s);
    char & operator[](int pos)
    {
        return p[pos];
    }
    int size()const{return strlen(p);}
    my_string operator+(my_string s)
    {
        my_string tmp;
        tmp.p= new char[this->size()+s.size()+1];
        strcpy(tmp.p,this->p);
        strcat(tmp.p,s.p);
        return tmp;
    }
    my_string operator+(const char* s)
    {
        my_string tmp;
        tmp.p= new char[this->size()+strlen(s)+1];
        strcpy(tmp.p,this->p);
        strcat(tmp.p,s);
        return tmp;
    }
};

ostream &operator<<(ostream&cout,my_string &s)
{
    cout<<s.p;
    return cout;
}

int main()
{
    my_string s="123";
    my_string s1="abc";
    my_string s2 =s+s1;//s2(s+s1);
//  cout<<s2<<endl;//123abc
//  my_string s3 = s1 + "mmm";
    //'a',"123" =const char*
    my_string s3 ;
    //此处会出现double free，因为此处的=是赋值运算，做的是浅拷贝
    s3= s1 + "mmm";
    cout<<s3<<endl;//123abc



    //s3 = s1+(s+s2);
//  s[0] = 'a';
//  cout<<s<<endl;
//  cout<<s[0]<<endl;
//  cout<<s<<endl;
//  cout<<sizeof(s)<<endl;

    return 0;
}