There are N gas stations along a circular route, where the amount of gas at station i is gas[i]
.
You have a car with an unlimited gas tank and it costs cost[i]
of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
思考:若sum<0,则可能从下一站开始。
class Solution { public: int canCompleteCircuit(vector<int> &gas, vector<int> &cost) { int n=gas.size(); int sum=0; int index=0; int total=0; for(int i=0;i<n;i++) { sum+=gas[i]-cost[i]; total+=gas[i]-cost[i]; if(sum<0) { index=(i+1)%n; sum=0; } } if(total<0) return -1; else return index; } };