There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
思考:既然是有序数组,自然想到折半搜索。每次比较去掉其中一个数组一半的数字。
class Solution { public: int func(int *A,int m,int *B,int n,int k) { if(m>n) return func(B,n,A,m,k); if(m==0) return B[k-1]; if(k==1) return min(A[0],B[0]); int pa=min(k/2,m); int pb=k-pa; if(A[pa-1]<B[pb-1]) return func(A+pa,m-pa,B,n,k-pa); else if(A[pa-1]>B[pb-1]) return func(A,m,B+pb,n-pb,k-pb); else return A[pa-1]; } double findMedianSortedArrays(int A[],int m, int B[],int n) { // Start typing your Java solution below // DO NOT write main() function int total=m+n; if(total&0x1) return func(A,m,B,n,total/2+1); else return (double)(func(A,m,B,n,total/2)+func(A,m,B,n,total/2+1))/2; } };