• Data Warehouse Hardware


    1. Disk I/O, 硬盘IO速度

      硬盘的IO速度一直都是数据库的瓶颈,所以有条件的情况下尽可能的使用高IO的磁盘。

      可以使用微软的工具SQLIO测试磁盘的IOPS

    2. CPU的主频,

      DW和传统的OLTP数据库在使用场景上不一样。

      传统的OLTP数据库具有[事务小][并发多]的特点;而DW的数据库相比较具有[事务大][并发少]的特点。

      所以对比起来,传统的OLTP数据库可以使用[低主频][多核]的硬件架构,而DW建议使用[高主频][少核]方案。

      上述都是相对情况,对于不差钱的土豪,高主频,多核当然是更好的选择。

    我们可以计算的是要满足具体的业务需求,需要多少CPU(Core),多少内存。

    MCR,Maximum Consumption Rate,这是一个Core的吞吐量指标

    3. 计算MCR

      可以使用下面的脚本计算出当前计算机的MCR

      

    USE master;
    
    -- Create a database for benchmark queries
    IF EXISTS (SELECT * FROM sys.sysdatabases WHERE name = 'BenchmarkDB')
    DROP DATABASE BenchMarkDB;
    GO
    CREATE DATABASE BenchMarkDB;
    GO
    USE BenchMarkDB;
    
    -- Include a heap and a table with a clustered index
    CREATE TABLE heap_table
    (col1 integer identity,
     col2 integer,
     col3 varchar(50));
    
     CREATE TABLE clust_table
    (col1 integer identity PRIMARY KEY CLUSTERED,
     col2 integer,
     col3 varchar(50));
    
    -- Insert 100 rows to start with
    DECLARE @i integer = 0;
    WHILE @i < 101
    BEGIN
       SET @i = @i + 1
       INSERT INTO heap_table VALUES (@i, CAST(@i%5 AS varchar))
       INSERT INTO clust_table VALUES (@i, CAST(@i%5 AS varchar))
    END;
    
    -- Now keep reinserting exponentially until the tables each contain 2 million rows
    WHILE (SELECT COUNT(*) FROM clust_table) < 2000000
    BEGIN
     INSERT INTO heap_table
     SELECT col2, col3 FROM clust_table;
     INSERT INTO clust_table
     SELECT col2, col3 FROM clust_table;
    END;
    USE BenchmarkDB
    GO
    
    SELECT SUM(Col2) FROM heap_table WHERE col1 % 3 = 1
    GROUP BY col3;
    
    SELECT SUM(Col2) FROM clust_table WHERE col1 % 3 = 1
    GROUP BY col3;
    
    
    SET STATISTICS IO ON;
    SET STATISTICS TIME ON;
    
    
    -- run these muliple times and take an average of the logical reads and CPU time
    SELECT SUM(Col2) FROM heap_table WHERE col1 % 3 = 1
    GROUP BY col3
    OPTION (MAXDOP 1);
    
    
    SELECT SUM(Col2) FROM clust_table WHERE col1 % 3 = 1
    GROUP BY col3
    OPTION (MAXDOP 1);
    
    /* Max Consumption Rate (MCR) is the average of (logical reads / CPU time in seconds) * 8 / 1024
      (or put another way, the size of the table in MB / CPU time in seconds)
      This gives us the throughput of a core
    
      To estimate the no. of cores required, use the following formula:
      (Amount of data scanned in an average query / MCR) * Concurrent Sessions / Target response time
      For example:
     (18000 MB/200 MBs) * 10 users / 60s response time = 15 cores (round up to 16)   */

    4. Memory内存需求

      最少1核对应4G内存,或者对每组CPU给64-128G内存

      

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  • 原文地址:https://www.cnblogs.com/Niko12230/p/6114283.html
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