列表解析练习题

'''
有两个列表，分别存放来老男孩报名学习linux和python课程的学生名字
linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao']
python=['dragon','钢弹','zhejiangF4','小虎比']
'''
# # 问题一：得出既报名linux又报名python的学生列表

## 常规方法
# linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao']
# python=['dragon','钢弹','zhejiangF4','小虎比']
# l=[]
# for i in linux:
#     for j in python:
#         if i==j:
#             l.append(i)

## 列表解析处理
# linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao']
# python=['dragon','钢弹','zhejiangF4','小虎比']
#
# l = [i for i in linux for j in python if i == j]
# print(l)

# # 问题二：得出只报名linux，而没有报名python的学生列表

# linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao']
# python=['dragon','钢弹','zhejiangF4','小虎比']
# l=[i for i in linux if i not in python]
# print(l)

# 问题三：得出只报名python，而没有报名linux的学生列表

'''
shares={
    'IBM':36.6,
    'lenovo':27.3,
    'huawei':40.3,
    'oldboy':3.2,
    'ocean':20.1
    }
'''
# # 问题一：得出股票价格大于30的股票名字列表
# shares={
#     'IBM':36.6,
#     'lenovo':27.3,
#     'huawei':40.3,
#     'oldboy':3.2,
#     'ocean':20.1
#     }
# s = [v for v in shares.values() if v > 30 ]
# print(s)
# # 问题二：求出所有股票的总价格
#
# l = [v for v in shares.values()]
# print(sum(l))

'''
l=[10,2,3,4,5,6,7]
得到一个新列表l1，新列表中每个元素是l中对应每个元素值的平方
过滤出l1中大于40的值，然后求和
'''
# l=[10,2,3,4,5,6,7]
# l1 = [ i**2 for i in l ]
# 
# l2 = [i for i in l1 if i > 40]
# print(sum(l2))