• HDU4614 Vases and Flowers


    http://acm.hdu.edu.cn/showproblem.php?pid=4614

     HDU 4614 Vases and Flowers (2013多校第二场线段树)

      1 // #pragma comment(linker, "/STACK:1024000000,1024000000")
      2 #include <iostream>
      3 #include <cstdio>
      4 #include <cstring>
      5 #include <sstream>
      6 #include <string>
      7 #include <algorithm>
      8 #include <list>
      9 #include <map>
     10 #include <vector>
     11 #include <queue>
     12 #include <stack>
     13 #include <cmath>
     14 #include <cstdlib>
     15 #include <conio.h>
     16 using namespace std;
     17 #define clc(a,b) memset(a,b,sizeof(a))
     18 #define inf 0x3f3f3f3f
     19 #define lson l,mid,rt<<1
     20 #define rson mid+1,r,rt<<1|1
     21 const int N = 50010;
     22 const int MOD = 1e9+7;
     23 #define LL long long
     24 #define mi() (l+r)>>1
     25 double const pi = acos(-1);
     26 void fre() {
     27     freopen("in.txt","r",stdin);
     28 }
     29 // inline int r() {
     30 //     int x=0,f=1;char ch=getchar();
     31 //     while(ch>'9'||ch<'0') {if(ch=='-') f=-1;ch=getchar();}
     32 //     while(ch>='0'&&ch<='9') { x=x*10+ch-'0';ch=getchar();}return x*f;
     33 // }
     34 struct Edge {
     35     int l,r;
     36     int lazy,sum;
     37 } e[N<<2];
     38 
     39 void pushdown(int rt) {
     40     e[rt].sum=e[rt<<1].sum+e[rt<<1|1].sum;
     41 }
     42 void pushup(int rt) {
     43     if(e[rt].lazy!=-1) {
     44         e[rt<<1].lazy=e[rt<<1|1].lazy=e[rt].lazy;
     45         e[rt<<1].sum=(e[rt<<1].r-e[rt<<1].l+1)*e[rt].lazy;
     46         e[rt<<1|1].sum=(e[rt<<1|1].r-e[rt<<1|1].l+1)*e[rt].lazy;
     47         e[rt].lazy=-1;
     48     }
     49 }
     50 
     51 void build(int l,int r,int rt) {
     52     e[rt].l=l;
     53     e[rt].r=r;
     54     e[rt].lazy=-1;
     55     if(l==r) {
     56         e[rt].sum=0;
     57         return;
     58     }
     59     int mid=mi();
     60     build(lson);
     61     build(rson);
     62     pushdown(rt);
     63 }
     64 
     65 int query(int l,int r,int rt) {
     66     if(e[rt].l==l&&e[rt].r==r) {
     67         return e[rt].sum;
     68     }
     69     pushup(rt);
     70     int mid=(e[rt].l+e[rt].r)>>1;
     71     if(r<=mid)  return query(l,r,rt<<1);
     72     else if(l>mid) return query(l,r,rt<<1|1);
     73     else return query(l,mid,rt<<1)+query(mid+1,r,rt<<1|1);
     74 }
     75 
     76 void update(int l,int r,int rt,int c){
     77      if(e[rt].l==l&&e[rt].r==r){
     78          e[rt].lazy=c;
     79          e[rt].sum=(e[rt].r-e[rt].l+1)*c;
     80          return;
     81      }
     82      pushup(rt);
     83      int mid=(e[rt].l+e[rt].r)>>1;
     84      if(r<=mid) update(l,r,rt<<1,c);
     85      else if(l>mid) update(l,r,rt<<1|1,c);
     86      else {
     87            update(l,mid,rt<<1,c);
     88            update(mid+1,r,rt<<1|1,c);
     89     }
     90      pushdown(rt);
     91 }
     92 
     93 int main() {
     94     // fre();
     95     int T;
     96     scanf("%d",&T);
     97     while(T--) {
     98         int n,q;
     99         cin>>n>>q;
    100         build(1,n,1);
    101         while(q--) {
    102             int op,a,b;
    103             cin>>op>>a>>b;
    104             if(op==1) {
    105                 int L=a+1,R=n;
    106                 int st,ed;
    107                 if((n-L+1-query(L,n,1))==0) {
    108                     printf("Can not put any one.
    ");
    109                     continue;
    110                 }
    111                 st=inf;
    112                 while(L<=R) {
    113                     int mid=(L+R)>>1;
    114                     if((mid-(a+1)+1-query(a+1,mid,1))>=1) {
    115                         st=min(st,mid);
    116                         R=mid-1;
    117                     } else {
    118                         L=mid+1;
    119                     }
    120                 }
    121                 int tem=n-st+1-query(st,n,1);
    122                 if(tem<b) b=tem;
    123                 ed=inf;
    124                 L=st,R=n;
    125                 while(L<=R) {
    126                     int mid=(L+R)>>1;
    127                     tem=mid-st+1-query(st,mid,1);
    128                     if(tem==b) {
    129                         ed=min(ed,mid);
    130                         R=mid-1;
    131                     } else if(tem>b) {
    132                         R=mid-1;
    133                     } else {
    134                         L=mid+1;
    135                     }
    136                 }
    137                 printf("%d %d
    ",st-1,ed-1);
    138                 update(st,ed,1,1);
    139             } else {
    140                  printf("%d
    ",query(a+1,b+1,1));
    141                  update(a+1,b+1,1,0);
    142             }
    143         }
    144         cout<<endl;
    145     }
    146     return 0;
    147 }
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  • 原文地址:https://www.cnblogs.com/ITUPC/p/5638659.html
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