在Linux内核中,设备树节点中的status属性的值决定了是否开启设备,当status属性没有在设备节点中定义时,默认设备是开启的。
关于设备树节点中status属性的处理的代码位于drivers/of/base.c文件中,有两个函数,如下所示:
/** * __of_device_is_available - check if a device is available for use * * @device: Node to check for availability, with locks already held * * Returns true if the status property is absent or set to "okay" or "ok", * false otherwise */ static bool __of_device_is_available(const struct device_node *device) { const char *status; int statlen; if (!device) return false; status = __of_get_property(device, "status", &statlen); if (status == NULL) return true; if (statlen > 0) { if (!strcmp(status, "okay") || !strcmp(status, "ok")) return true; } return false; } /** * of_device_is_available - check if a device is available for use * * @device: Node to check for availability * * Returns true if the status property is absent or set to "okay" or "ok", * false otherwise */ bool of_device_is_available(const struct device_node *device) { unsigned long flags; bool res; raw_spin_lock_irqsave(&devtree_lock, flags); res = __of_device_is_available(device); raw_spin_unlock_irqrestore(&devtree_lock, flags); return res; } EXPORT_SYMBOL(of_device_is_available);
从代码中,可以知道,当默认没有定义status属性时,函数将返回true,也就是默认是开启设备的,另外,想要在设备节点中开启设备,可以将status属性的值定义为"ok"或者"okay"。