• UVA 10603 Fill 最短路


    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("in.txt","r",stdin);
        //freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    struct HeapNode
    {
        int d,u;
        bool operator < (const HeapNode &ant) const
        {
            return d>ant.d;
        }
    };
    struct Edge
    {
        int from,to;
        int dist;
    };
    const int maxn=41005;
    struct Dijksta
    {
        int n;
        vector<int> g[maxn];
        vector<Edge> edge;
        int done[maxn];
        int d[maxn];
    
        void init(int n)
        {
            this->n=n;
            for(int i=0;i<=n;i++)
                g[i].clear();
            edge.clear();
        }
    
        void add(int u,int v,int w)
        {
            Edge e=(Edge){u,v,w};
            edge.push_back(e);
            g[u].push_back(edge.size()-1);
        }
    
        void solve(int s)
        {
            for(int i=0;i<=n;i++)d[i]=INF;
            memset(done,0,sizeof(done));
            priority_queue<HeapNode> q;
            q.push((HeapNode){0,s});
            d[s]=0;
            while(!q.empty())
            {
                HeapNode x=q.top();q.pop();
                if(done[x.u])continue;
                int u=x.u;
                done[u]=1;
                for(int i=0;i<g[u].size();i++)
                {
                    Edge &e=edge[g[u][i]];
                    if(d[u]+e.dist<d[e.to])
                    {
                        d[e.to]=d[u]+e.dist;
                        q.push((HeapNode){d[e.to],e.to});
                    }
                }
            }
        }
    };
    
    Dijksta solver;
    int d;
    int A[3],a[3];
    int total;
    int id[205][205];
    int vcnt;
    int ID(int a,int b)
    {
        int &x=id[a][b];
        if(x==0)x=++vcnt;
        return x;
    }
    
    void pour(int i,int j)
    {
        int b[3];
        memcpy(b,a,sizeof(a));
        if(b[i]!=0&&b[i]+b[j]<=A[j])
        {
            b[j]+=b[i];
            b[i]=0;
            solver.add(ID(a[0],a[1]),ID(b[0],b[1]),a[i]);
        }
        memcpy(b,a,sizeof(a));
        if(b[i]!=0&&b[i]+b[j]>A[j])
        {
            b[i]=b[i]-(A[j]-b[j]);
            b[j]=A[j];
            solver.add(ID(a[0],a[1]),ID(b[0],b[1]),A[j]-a[j]);
        }
    }
    void construct()
    {
        for(a[0]=0;a[0]<=A[0];a[0]++)
            for(a[1]=0;a[1]+a[0]<=total&&a[1]<=A[1];a[1]++)
            {
                a[2]=total-a[0]-a[1];
                pour(0,1);pour(0,2);
                pour(1,0);pour(1,2);
                pour(2,0);pour(2,1);
            }
    }
    
    void find(int &ans1,int &ans2)
    {
        ans1=INF;
        for(ans2=d;ans2>=0;ans2--)
        {
            for(int a=0;a<=A[0];a++)
            {
                for(int b=0;b+a<=total&&b<=A[1];b++)
                {
                    int c=total-a-b;
                    if((solver.d[ID(a,b)]!=INF)&&(a==ans2||b==ans2||c==ans2))
                    {
                        ans1=min(ans1,solver.d[ID(a,b)]);
                    }
                }
            }
            if(ans1!=INF)return ;
        }
    }
    int main()
    {
        //freopen("in.txt","r",stdin);
        int t;scanf("%d",&t);
        for(int ca=1;ca<=t;ca++)
        {
            for(int i=0;i<3;i++)scanf("%d",&A[i]);
            scanf("%d",&d);
            total=A[2];
            solver.init((A[0]+1)*(A[1]+1));
            vcnt=0;
            memset(id,0,sizeof(id));
            construct();
    
            solver.solve(ID(0,0));
            int ans1,ans2;
            find(ans1,ans2);
            printf("%d %d
    ",ans1,ans2);
    
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3647153.html
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