• POJ 3050


    我是开了个六维的数组来记住它的每一步

     1 #include <cstdio>
     2 #include <cstring>
     3 #include <cstdlib>
     4 #include <cctype>
     5 #include <cmath>
     6 #include <time.h>
     7 #include <string>
     8 #include <map>
     9 #include <stack>
    10 #include <set>
    11 #include <queue>
    12 #include <vector>
    13 #include <algorithm>
    14 #include <iostream>
    15 using namespace std;
    16 typedef long long ll;
    17 typedef pair<int,int> P;
    18 #define PI acos( -1.0 )
    19 const double E = 1e-8;
    20 const int INF = 0x7fffffff;
    21 
    22 int a[10][10], b[10];
    23 int dir[][2] = { 0, -1, 0, 1, -1, 0, 1, 0 };
    24 int mark[10][10][10][10][10][10];
    25 int ans = 0;
    26 
    27 void dfs( int x, int y, int num )
    28 {
    29     if( num == 7 )
    30     {
    31         if( !mark[b[0]][b[1]][b[2]][b[3]][b[4]][b[5]] )
    32         {
    33             mark[b[0]][b[1]][b[2]][b[3]][b[4]][b[5]] = 1;
    34             ++ans;
    35         }
    36         return;
    37     }
    38     for( int k = 0; k < 4; ++k )
    39     {
    40         int dx = x + dir[k][0];
    41         int dy = y + dir[k][1];
    42         if( dx >= 0 && dy >= 0 && dy< 5 && dx < 5 ) {
    43             b[num] = a[dx][dy];
    44             dfs( dx, dy, num+1 );
    45         }
    46     }
    47 }
    48 
    49 int main()
    50 {
    51     for( int i = 0; i < 5; ++i )
    52         for( int j = 0; j < 5; ++j )
    53             scanf( "%d", a[i]+j );
    54     memset( mark, 0, sizeof( mark ) );
    55     for( int i = 0; i < 5; ++i )
    56         for( int j = 0; j < 5; ++j ) {
    57             b[0] = a[i][j];
    58             dfs( i, j, 1 );
    59         }
    60     printf( "%d
    ", ans );
    61     return 0;
    62 }
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  • 原文地址:https://www.cnblogs.com/ADAN1024225605/p/4095935.html
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