• LeetCode 27. Remove Element


    Given an array nums and a value val, remove all instances of that value in-place and return the new length.

    Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

    The order of elements can be changed. It doesn't matter what you leave beyond the new length.

    Example 1:

    Given nums = [3,2,2,3], val = 3,
    
    Your function should return length = 2, with the first two elements of nums being 2.
    
    It doesn't matter what you leave beyond the returned length.
    

    Example 2:

    Given nums = [0,1,2,2,3,0,4,2], val = 2,
    
    Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.
    
    Note that the order of those five elements can be arbitrary.
    

    It doesn't matter what values are set beyond the returned length.
    Clarification:

    Confused why the returned value is an integer but your answer is an array?

    Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.

    Internally you can think of this:

    // nums is passed in by reference. (i.e., without making a copy)
    int len = removeElement(nums, val);
    
    // any modification to nums in your function would be known by the caller.
    // using the length returned by your function, it prints the first len elements.
    for (int i = 0; i < len; i++) {
        print(nums[i]);
    }
    
    class Solution { //水题
    public:
        int removeElement(vector<int>& nums, int val) {
            for(auto it = nums.begin(); it!=nums.end(); it++)
                if(*it==val){
                    nums.erase(it);
                    it--;
                }
            return nums.size();
        }
    };
    
  • 相关阅读:
    C#使用System.IO.Path获取文件路径、文件名
    C# 中的await
    深度学习笔记
    单例模式
    hbase的写和读,大合并和小合并
    自定义kafka Sink
    combineByKey
    spark练习题
    sparkonhbase
    HDFS只支持文件append操作, 而依赖HDFS的HBase如何完成增删改查功能
  • 原文地址:https://www.cnblogs.com/A-Little-Nut/p/9834723.html
Copyright © 2020-2023  润新知