Description
A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :
- A box fractal of degree 1 is simply
X - A box fractal of degree 2 is
X X
X
X X - If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
B(n - 1) B(n - 1)
B(n - 1)
B(n - 1) B(n - 1)
Your task is to draw a box fractal of degree n.
Input
The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7. The last line of input is a negative integer −1 indicating the end of input.
Output
For each test case, output the box fractal using the 'X' notation. Please notice that 'X' is an uppercase letter. Print a line with only a single dash after each test case.
Sample Input
1 2 3 4 -1
Sample Output
X - X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X -
解析
一道比较简单的分形图,n<=7,则边长最大为739,开一个800*800的数组记录当前是“X”还是“ ”,当他处于第n级时,如果需要向n-1级递归,就有五个方向:
左上角,右上角,中间,左下角,右下角。
#include<cstring> #include<cstdio> #include<cmath> using namespace std; int n; bool maps[1000][1000]; inline void dfs(int m,int bian,int xx,int yy) { if(m==1){ maps[xx][yy]=1; return; } dfs(m-1,bian/3,xx-bian/3,yy-bian/3); dfs(m-1,bian/3,xx-bian/3,yy+bian/3); dfs(m-1,bian/3,xx+bian/3,yy-bian/3); dfs(m-1,bian/3,xx+bian/3,yy+bian/3); dfs(m-1,bian/3,xx,yy); } int main() { while(1) { memset(maps,0,sizeof maps); scanf("%d",&n); if(n==-1)break; int bian=1; for(int i=1;i<=n-1;i++) bian*=3; dfs(n,bian,(bian+1)/2,(bian+1)/2);//分别传入第n级,边长(长 和 高相等),中心位置的横纵坐标 for(register int i=1;i<=bian;i++) { for(register int j=1;j<=bian;j++) { if(maps[i][j])printf("X"); else printf(" "); } printf(" "); } printf("- "); } }