• 支持正则或通配符的hashmap


    RegexpKeyedMap

     http://wiki.apache.org/jakarta/RegexpKeyedMap

    RegexHashMap

    https://heideltime.googlecode.com/hg-history/a354341d349e75262884706b830f237fd9eeb269/src/de/unihd/dbs/uima/annotator/heideltime/resources/RegexHashMap.java

    原理基本都是get的时候去遍历key值,逐个正则匹配,效率不高。

    nginx有支持通配符的实现,有时间可以了解下实现。

    RegexHashMap

    package de.unihd.dbs.uima.annotator.heideltime.resources;
    
    import java.util.Collection;
    import java.util.HashMap;
    import java.util.HashSet;
    import java.util.Iterator;
    import java.util.Map;
    import java.util.Set;
    import java.util.regex.Pattern;
    
    /**
     * Implements a HashMap extended with regular expression keys and caching functionality.
     *  
     * @author Julian Zell
     *
     */
    public class RegexHashMap<T> implements Map<String, T> {
        
        private HashMap<String, T> container = new HashMap<String, T>();
        private HashMap<String, T> cache = new HashMap<String, T>();
        
        /**
         * clears both the container and the cache hashmaps
         */
        public void clear() {
            container.clear();
            cache.clear();
        }
        
        /**
         * checks whether the cache or container contain a specific key, then evaluates the
         * container's keys as regexes and checks whether they match the specific key.
         */
        public boolean containsKey(Object key) {
            // the key is a direct hit from our cache
            if(cache.containsKey(key))
                return true;
            // the key is a direct hit from our hashmap
            if(container.containsKey(key))
                return true;
    
            // check if the requested key is a matching string of a regex key from our container
            Iterator<String> regexKeys = container.keySet().iterator();
            while(regexKeys.hasNext()) {
                if(Pattern.matches(regexKeys.next(), (String) key))
                    return true;
            }
            
            // if the three previous tests yield no result, the key does not exist
            return false;
        }
        
        /**
         * checks whether a specific value is container within either container or cache
         */
        public boolean containsValue(Object value) {
            // the value is a direct hit from our cache
            if(cache.containsValue(value))
                return true;
            // the value is a direct hit from our hashmap
            if(container.containsValue(value))
                return true;
            
            // otherwise, the value isn't within this object
            return false;
        }
        
        /**
         * returns a merged entryset containing within both the container and cache entrysets
         */
        public Set<Entry<String, T>> entrySet() {
            // prepare the container
            HashSet<Entry<String, T>> set = new HashSet<Entry<String, T>>();
            // add the set from our container
            set.addAll(container.entrySet());
            // add the set from our cache
            set.addAll(cache.entrySet());
            
            return set;
        }
        
        /**
         * checks whether the requested key has a direct match in either cache or container, and if it
         * doesn't, also evaluates the container's keyset as regexes to match against the input key and
         * if any of those methods yield a value, returns that value
         * if a value is found doing regex evaluation, use that regex-key's match as a non-regex 
         * key with the regex's value to form a new entry in the cache.
         */
        public T get(Object key) {
            // output for requested key null is the value null; normal Map behavior
            if(key == null) return null;
            
            T result = null;
            if((result = cache.get(key)) != null) {
                // if the requested key maps to a value in the cache
                return result;
            } else if((result = container.get(key)) != null) {
                // if the requested key maps to a value in the container
                return result;
            } else {
                // check if the requested key is a matching string of a regex key from our container
                Iterator<Entry<String, T>> regexKeys = container.entrySet().iterator();
                while(regexKeys.hasNext()) {
                    // prepare current entry
                    Entry<String, T> entry = regexKeys.next();
                    // check if the key is a regex matching the input key
                    if(Pattern.matches(entry.getKey(), (String) key)) {
                        putCache((String) key, entry.getValue());
                        return entry.getValue();
                    }
                }
            }
            
            // no value for the given key was found in any of container/cache/regexkey-container
            return null;
        }
    
        /**
         * checks whether both container and cache are empty
         */
        public boolean isEmpty() {
            return container.isEmpty() && cache.isEmpty();
        }
        
        /**
         * returns the keysets of both the container and cache hashmaps 
         */
        public Set<String> keySet() {
            // prepare container
            HashSet<String> set = new HashSet<String>();
            // add container keys
            set.addAll(container.keySet());
            // add cache keys
            set.addAll(cache.keySet());
            
            return set;
        }
        
        /**
         * associates a key with a value in the container hashmap
         */
        public T put(String key, T value) {
            return container.put(key, value);
        }
        
        /**
         * associates a key with a value in the cache hashmap.
         * @param key Key to map from
         * @param value Value to map to
         * @return previous value associated with the key, or null if unassociated before
         */
        public T putCache(String key, T value) {
            return cache.put(key, value);
        }
    
        /**
         * adds a map to the container
         */
        public void putAll(Map<? extends String, ? extends T> m) {
            container.putAll(m);
        }
    
        /**
         * removes a specific key's association from the container
         */
        public T remove(Object key) {
            return container.remove(key);
        }
        
        /**
         * returns the combined size of container and cache
         */
        public int size() {
            return container.size() + cache.size();
        }
    
        /**
         * returns the combined collection of both the values of the container as well as
         * the cache.
         */
        public Collection<T> values() {
            // prepare set
            HashSet<T> set = new HashSet<T>();
            // add all container values
            set.addAll(container.values());
            // add all cache values
            set.addAll(cache.values());
            
            return set;
        }    
    }

    RegexpKeyedMap

    package org.apache.regexp.collections;
    
    import java.util.HashMap;
    import java.util.Iterator;
    
    import org.apache.regexp.RE;
    import org.apache.regexp.RESyntaxException;
    
    
    
    /**
     * This map implementation uses a hashmap as the underlying storage.  
     * Note that the keySet() method will return a set of regular expressions rather than actual keys.
     * The put() method uses a regexp as a key.
     * The get() method gets any value that matches one of the regexps.  If there is more than one matching regexp, the first one 
     * encountered is returned - and hence could be indeterminate!
     * 
     * @author Manik Surtani
     *
     */
    public class RegexpKeyedMap extends HashMap
    {
        public Object put(Object key, Object value)
        {
            if (key instanceof String)
                return super.put(key, value);
            else
                throw new RuntimeException("RegexpKeyedMap - only accepts Strings as keys.");    
        }
            
        /**
         * The key passed in should always be a String.  The map will return the first element whose key, treated as a regular expression, matches the key passed in
         * NOTE: It is possible for this map to have more than one return value, for example, if a key is passed into get() which matches more than one regexp.
         * 
         * E.g., consider the following keys in the map - '[A-Za-z]*' and 'Hello'.  Passing in 'Hello' as a key to the get() method would match either of the regexps,
         * and whichever apears first in the map (which is indeterminate) will be returned. 
         *
         */
        public Object get(Object key)
        {
            Iterator regexps = keySet().iterator();
            String keyString;
            Object result = null;
            
            String stringToMatch = cleanKey( key );
            
            while (regexps.hasNext())
            {
                keyString = regexps.next().toString();
                try
                {
                    RE regexp = new RE(keyString);
                    if (regexp.match(stringToMatch))
                    {
                        result = super.get(keyString);
                        break;
                    }
                }
                catch (RESyntaxException e)
                {
                    // invalid regexp.  ignore?
                }
            }
            return result;
        }
        
        /**
         * Strip any 'dirty' chars from the key we are searching for, 
         * otherwise we end up with funny results from the RE
         * 
         * @param obj
         * @return
         */
        private String cleanKey( Object obj )
        {
            String retVal = obj.toString();
            
            // remove any '^' from start of key - prevents the RE from matching !?!?  
            return ( retVal.charAt(0) == '^' )  ? retVal.substring(1) : retVal;
        }
        
    }
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  • 原文地址:https://www.cnblogs.com/549294286/p/4891856.html
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