1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)
package javazy; import java.util.Scanner; public class one { public static void main(String[] args) { // TODO Auto-generated method stub System.out.print("输入年份:"); Scanner sc=new Scanner(System.in); String str=sc.nextLine(); if(str.length()!=4){ System.out.print("请输入正确的四位数!"); return; } int year=Integer.parseInt(str); if((year%4==0&&year%100!=0||year%400==0)) System.out.print(year+"是闰年!"); }else{ System.out.print(year+"不是闰年!"); } }
}
2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.
package javazy; import java.util.Scanner; public class two { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); System.out.println("请输入四位卡号"); int a=input.nextInt(); if((a%1000/100)%3==0){ System.out.println("是幸运会员"); }else{ System.out.println("不是幸运会员"); } } }
3.已知函数,输入x的值,输出对应的y的值.
x + 3 ( x > 0 )
y = 0 ( x = 0 )
x*2 –1 ( x < 0 )
package javazy; import java.util.Scanner; public class three { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input= new Scanner(System.in); System.out.println("输入x的值"); float x=input.nextInt(); float y; if(x>0){ y=x+3; }else if(x==0){ y=0; }else{ y=x*x-1; } System.out.println(y); } }
4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)
package javazy; import java.util.Scanner; public class four { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc= new Scanner(System.in); System.out.println("请输入第一个数:"); double x= sc.nextDouble(); System.out.println("请输入第二个数:"); double y= sc.nextDouble(); System.out.println("请输入第三个数:"); double z= sc.nextDouble(); double i=x+y; double h=x+z; double l=y+z; if(x>=l || y>=h || z>=i) { System.out.println("不能构成三角形"); }else { System.out.println("能构成三角形"); } } }