• hdu1686 KMP 求在字符串A中字符串B出现的次数


    Oulipo

    Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 24592    Accepted Submission(s): 9516


    Problem Description
    The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

    Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

    Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

    So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

     
    Input
    The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

    One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
    One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
     
    Output
    For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

     
    Sample Input
    3
    BAPC
    BAPC
    AZA
    AZAZAZA
    VERDI
    AVERDXIVYERDIAN
     
    Sample Output
    1
    3
    0
     
    //HD1686
    #include<iostream>
    #include<algorithm>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    const int N = 1000005;
    int i, n, m, t, sum;
    char T[N], P[N];//P[]是需要比较的字符串,T[]是被比较的字符串
    int next1[N];
    
    void getnext(char  *P, int *next1)
    {
        int j = 0;
        int k = -1;
        next1[0] = -1;
        while (j<m)
        {
            if (k == -1 || P[j] == P[k])
            {
                next1[++j] = ++k;
            }
            else
            {
                k = next1[k];
            }
        }
    }
    int KMP(char *T, char *P)
    {
        sum = 0;
        int i = 0;
        int j = 0;
        getnext(P, next1);
        while (i<n&&j<m)//注意这里的等号要不要取
        {        
            if (j == -1 || T[i] == P[j])//匹配的情况,坐标后移
            {
                i++;
                j++;
            }
            else//如果不匹配
            {
                j = next1[j];
            }
            if (j == m)//判断是否匹配结束
            {
                sum++;
            }
        }
        return sum;
    }
    int main()
    {
        scanf("%d", &t);
        for (int i = 0; i<t; i++)
        {        
            scanf("%s%s", T, P);
            m = strlen(P);
            n = strlen(T);
            printf("%d
    ", KMP(T, P));
        }
        //system("pause");
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/-citywall123/p/10034286.html
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