• Java中Json解析


    首先准备一个JSON格式的字符串
    * String JsonStr = "{object:{persons:" +
    "[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," +
    "{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," +
    "{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}";

    * 然后定义一个Person类
    *
    *

     1 class Person{
     2     private String name,image;
     3 
     4     public String getName() {
     5         return name;
     6     }
     7 
     8     public void setName(String name) {
     9         this.name = name;
    10     }
    11 
    12     public String getImage() {
    13         return image;
    14     }
    15 
    16     public void setImage(String image) {
    17         this.image = image;
    18     }
    19     
    20 }

    下面是一个Json解析的程序代码

     1 class MyDay17Xml {
     2     //json字符串
     3     static String JsonStr = "{object:{persons:" +
     4             "[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," +
     5             "{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," +
     6             "{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}";
     7 
     8     public static void main(String []args) throws JSONException{
     9         List<Person> list=jsonStrToList(JsonStr);
    10         System.out.println(list.size());
    11     }
    12     /**
    13      * 
    14      * 
    15      * 
    16      */
    17     public static List<Person> jsonStrToList(String jsonStr) throws JSONException{
    18         List<Person> list=new ArrayList<Person>();
    19         
    20         //通过字符串,获得最外部的json对象
    21         JSONObject jsonObj=new JSONObject(jsonStr);
    22         //通过属性名,获得内部的对象
    23         JSONObject jsonPersons=jsonObj.getJSONObject("object");
    24         //获得json对象组
    25         JSONArray arr=jsonPersons.getJSONArray("persons");
    26         for(int i=0;i<arr.length();i++){
    27             //循环对象,并通过getString("属性名");来获得值
    28             JSONObject tempJson=arr.getJSONObject(i);
    29             Person person=new Person();
    30             
    31             person.setName(tempJson.getString("name"));
    32             person.setImage(tempJson.getString("image"));
    33             list.add(person);
    34         }
    35         return list;
    36         
    37     }
    38     
    39 }
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  • 原文地址:https://www.cnblogs.com/zxxiaoxia/p/4320855.html
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