• Linq练习题


    1 、 查询 Student 表中的所有记录的 Sname 、 Ssex 和 Class 列。 
    select sname,ssex,class from student 
    Linq: 
        from s in Students
        select new {
            s.SNAME,
            s.SSEX,
            s.CLASS
        }
    Lambda:
        Students.Select( s => new {
            SNAME = s.SNAME,SSEX = s.SSEX,CLASS = s.CLASS
        })


    2 、 查询教师所有的单位即不重复的 Depart 列。 
    select distinct depart from teacher 
    Linq: 
        from t in Teachers.Distinct()
        select t.DEPART
    Lambda:
        Teachers.Distinct().Select( t => t.DEPART)

    3 、 查询 Student 表的所有记录。 
    select * from student 
    Linq: 
        from s in Students
        select s
    Lambda:
        Students.Select( s => s)


    4 、 查询 Score 表中成绩在 60 到 80 之间的所有记录。 
    select * from score where degree between 60 and 80 
    Linq:
        from s in Scores
        where s.DEGREE >= 60 && s.DEGREE < 80
        select s 
    Lambda:
        Scores.Where( 
            s => (
                    s.DEGREE >= 60 && s.DEGREE < 80 
                 )
        )

    5 、 查询 Score 表中成绩为 85 , 86 或 88 的记录。 
    select * from score where degree in (85,86,88)
    Linq:
    In
        from s in Scores
        where (
                new decimal[]{85,86,88}
              ).Contains(s.DEGREE)
        select s
    Lambda:
        Scores.Where( s => new Decimal[] {85,86,88}.Contains(s.DEGREE))
    Not in
        from s in Scores
        where !(
                new decimal[]{85,86,88}
              ).Contains(s.DEGREE)
        select s
    Lambda:
        Scores.Where( s => !(new Decimal[]{85,86,88}.Contains(s.DEGREE)))

        Any() 应用:双表进行 Any 时,必须是主键为 (String)
        CustomerDemographics CustomerTypeID ( String ) 
        CustomerCustomerDemos (CustomerID CustomerTypeID) (String)
        一个主键与二个主建进行 Any( 或者是一对一关键进行 Any)
        不可,以二个主键于与一个主键进行 Any
        
        from e in CustomerDemographics
        where !e.CustomerCustomerDemos.Any()
        select e
        
        from c in Categories
        where !c.Products.Any()
        select c

    6 、 查询 Student 表中 "95031" 班或性别为 " 女 " 的同学记录。 
    select * from student where class ='95031' or ssex= N' 女 '
    Linq:
        from s in Students
        where s.CLASS == "95031" 
           || s.CLASS == " 女 "
        select s
    Lambda:
        Students.Where(s => ( s.CLASS == "95031" || s.CLASS == " 女 "))


    7 、 以 Class 降序查询 Student 表的所有记录。 
    select * from student order by Class DESC
    Linq:
        from s in Students
        orderby s.CLASS descending
        select s
    Lambda:
        Students.OrderByDescending(s => s.CLASS)

    8 、 以 Cno 升序、 Degree 降序查询 Score 表的所有记录。 
    select * from score order by Cno ASC,Degree DESC
    Linq:( 这里 Cno ASC 在 linq 中要写在最外面 )
        from s in Scores
        orderby s.DEGREE descending
        orderby s.CNO ascending 
        select s
    Lambda:
        Scores.OrderByDescending( s => s.DEGREE)
              .OrderBy( s => s.CNO)


    9 、 查询 "95031" 班的学生人数。 
    select count(*) from student where class = '95031'
    Linq:
        (    from s in Students
            where s.CLASS == "95031"
            select s
        ).Count()
    Lambda:
        Students.Where( s => s.CLASS == "95031" )
                    .Select( s => s)
                        .Count()

    10 、查询 Score 表中的最高分的学生学号和课程号。 
    select distinct s.Sno,c.Cno from student as s,course as c ,score as sc 
    where s.sno=(select sno from score where degree = (select max(degree) from score))
    and c.cno = (select cno from score where degree = (select max(degree) from score))
    Linq:
        (
            from s in Students
            from c in Courses
            from sc in Scores
            let maxDegree = (from sss in Scores
                            select sss.DEGREE
                            ).Max()
            let sno = (from ss in Scores
                    where ss.DEGREE == maxDegree
                    select ss.SNO).Single().ToString()
            let cno = (from ssss in Scores
                    where ssss.DEGREE == maxDegree
                    select ssss.CNO).Single().ToString()
            where s.SNO == sno && c.CNO == cno
            select new {
                s.SNO,
                c.CNO
            }
        ).Distinct()
    操作时问题?执行时报错: where s.SNO == sno (这行报出来的) 运算符 "==" 无法应用于 "string" 和 "System.Linq.IQueryable<string>" 类型的操作数 
    解决: 
    原: let sno = (from ss in Scores
                    where ss.DEGREE == maxDegree
                    select ss.SNO).ToString()
    Queryable().Single() 返回序列的唯一元素;如果该序列并非恰好包含一个元素,则会引发异常。 
    解: let sno = (from ss in Scores
                    where ss.DEGREE == maxDegree
                    select ss.SNO).Single().ToString()

    11 、查询 '3-105' 号课程的平均分。 
    select avg(degree) from score where cno = '3-105' 
    Linq:
        (
            from s in Scores
            where s.CNO == "3-105"
            select s.DEGREE
        ).Average()
    Lambda:
        Scores.Where( s => s.CNO == "3-105")
                .Select( s => s.DEGREE)
                    .Average()


    12 、查询 Score 表中至少有 5 名学生选修的并以 3 开头的课程的平均分数。 
    select avg(degree) from score where cno like '3%' group by Cno having count(*)>=5 
    Linq:
            from s in Scores
            where s.CNO.StartsWith("3")
            group s by s.CNO
            into cc
            where cc.Count() >= 5
            select cc.Average( c => c.DEGREE)
    Lambda:
        Scores.Where( s => s.CNO.StartsWith("3") )
                .GroupBy( s => s.CNO )
                  .Where( cc => ( cc.Count() >= 5) )
                    .Select( cc => cc.Average( c => c.DEGREE) )
    Linq: SqlMethod
    like 也可以这样写 :
        s.CNO.StartsWith("3") or SqlMethods.Like(s.CNO,"%3")

    13 、查询最低分大于 70 ,最高分小于 90 的 Sno 列。 
    select sno from score group by sno having min(degree) > 70 and max(degree) < 90
    Linq:
        from s in Scores
        group s by s.SNO
        into ss
        where ss.Min(cc => cc.DEGREE) > 70 && ss.Max( cc => cc.DEGREE) < 90
        select new
        {
            sno = ss.Key
        }
    Lambda:
        Scores.GroupBy (s => s.SNO)
                   .Where (ss => ((ss.Min (cc => cc.DEGREE) > 70) && (ss.Max (cc => cc.DEGREE) < 90)))
                       .Select ( ss => new {
                                            sno = ss.Key
                                         })

    14 、查询所有学生的 Sname 、 Cno 和 Degree 列。 
    select s.sname,sc.cno,sc.degree from student as s,score as sc where s.sno = sc.sno
    Linq:
        from s in Students
        join sc in Scores
        on s.SNO equals sc.SNO
        select new
        {
            s.SNAME,
            sc.CNO,
            sc.DEGREE
        }
    Lambda:
        Students.Join(Scores, s => s.SNO,
                              sc => sc.SNO, 
                              (s,sc) => new{
                                                  SNAME = s.SNAME,
                                                CNO = sc.CNO,
                                                DEGREE = sc.DEGREE
                                              })

    15 、查询所有学生的 Sno 、 Cname 和 Degree 列。 
    select sc.sno,c.cname,sc.degree from course as c,score as sc where c.cno = sc.cno
    Linq:
        from c in Courses
        join sc in Scores
        on c.CNO equals sc.CNO
        select new
        {
            sc.SNO,c.CNAME,sc.DEGREE
        }
    Lambda:
        Courses.Join ( Scores, c => c.CNO, 
                                 sc => sc.CNO, 
                                 (c, sc) => new 
                                            {
                                                SNO = sc.SNO, 
                                                CNAME = c.CNAME, 
                                                DEGREE = sc.DEGREE
                                            })

    16 、查询所有学生的 Sname 、 Cname 和 Degree 列。 
    select s.sname,c.cname,sc.degree from student as s,course as c,score as sc where s.sno = sc.sno and c.cno = sc.cno
    Linq:
        from s in Students
        from c in Courses
        from sc in Scores
        where s.SNO == sc.SNO && c.CNO == sc.CNO
        select new { s.SNAME,c.CNAME,sc.DEGREE }

     
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  • 原文地址:https://www.cnblogs.com/zxtceq/p/5619200.html
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