• sql


    SELECT     info.ShopID, info.AreaID, info.Name, info.VehicleInfo, info.OrderNo, info.Tel, info.Tag, info.Address, info.Description, info.RecommendInfo,
                          info.ShopMap, info.ImagePath, info.OriginalPrice, info.SalePrice, info.ImageName, info.CreateTime, info.IsRecommend, g.avgvalue,
                          dbo.School.SchoolName, dbo.ShopType.TypeName, dbo.ShopType.ParentID, info.SchoolID, dbo.ShopType.TypeID
    FROM         dbo.ShopInfo AS info LEFT OUTER JOIN
                          dbo.School ON info.SchoolID = dbo.School.SchoolID LEFT OUTER JOIN
                          dbo.ShopType ON info.ShopTypeID = dbo.ShopType.TypeID LEFT OUTER JOIN
                              (SELECT     ShopID, AVG(Money) AS avgvalue
                                FROM          dbo.Grade
                                GROUP BY ShopID) AS g ON info.ShopID = g.ShopID




    select aa.*,bb.test from info as aa,(select InfoID,avg(avgvalue) as test from grade group by gradeid)as  bb where aa.InfoID=bb.InfoID
  • 相关阅读:
    Spring4
    Mysql索引优化、JMM内存模型
    深入浅出JVM
    ZGC垃圾搜集器
    Hibernate4基础
    红楼梦 各版本及资料
    JavaME环境配置
    5.1 Intent
    4.3 异步任务
    4.2.2 网络编程之Socket
  • 原文地址:https://www.cnblogs.com/zwei1121/p/643066.html
Copyright © 2020-2023  润新知