• PAT (Advanced Level) 1012. The Best Rank (25)


    简单排序题。

    注意:分数相同的人排名相同。

    #include<iostream>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<cstdio>
    #include<map>
    using namespace std;
    
    struct X
    {
        int k;
        int id;
        int f1,f2,f3,f4;
        int r[6];
    }s[5000];
    int n,m;
    map<int,int>z;
    
    int get(int a,int b,int c)
    {
        double sum=1.0*a+1.0*b+1.0*c;
        sum=sum/3+0.5;
        int res=(int)sum;
        return res;
    }
    
    bool cmp1(const X&a,const X&b){return a.f1>b.f1;}
    bool cmp2(const X&a,const X&b){return a.f2>b.f2;}
    bool cmp3(const X&a,const X&b){return a.f3>b.f3;}
    bool cmp4(const X&a,const X&b){return a.f4>b.f4;}
    bool cmp5(const X&a,const X&b){return a.k<b.k;}
    
    int main()
    {
        scanf("%d%d",&n,&m); z.clear();
        for(int i=1;i<=n;i++)
        {
            scanf("%d%d%d%d",&s[i].id,&s[i].f2,&s[i].f3,&s[i].f4);
            s[i].f1=get(s[i].f2,s[i].f3,s[i].f4);
            z[s[i].id]=i;
            s[i].k=i;
        }
    
        s[0].f1=s[0].f2=s[0].f3=s[0].f4=-456;
    
        sort(s+1,s+1+n,cmp1);
        for(int i=1;i<=n;i++)
        {
            if(s[i].f1==s[i-1].f1) s[i].r[1]=s[i-1].r[1];
            else s[i].r[1]=i;
        }
    
        sort(s+1,s+1+n,cmp2);
        for(int i=1;i<=n;i++)
        {
            if(s[i].f2==s[i-1].f2) s[i].r[2]=s[i-1].r[2];
            else s[i].r[2]=i;
        }
    
        sort(s+1,s+1+n,cmp3);
        for(int i=1;i<=n;i++)
        {
            if(s[i].f3==s[i-1].f3) s[i].r[3]=s[i-1].r[3];
            else s[i].r[3]=i;
        }
    
        sort(s+1,s+1+n,cmp4);
        for(int i=1;i<=n;i++)
        {
            if(s[i].f4==s[i-1].f4) s[i].r[4]=s[i-1].r[4];
            else s[i].r[4]=i;
        }
    
        sort(s+1,s+1+n,cmp5);
    
        for(int i=1;i<=m;i++)
        {
            int id; scanf("%d",&id);
            if(z[id]==0) printf("N/A
    ");
            else
            {
                int Min=9999;
                for(int j=1;j<=4;j++)
                    Min=min(Min,s[z[id]].r[j]);
                for(int j=1;j<=4;j++)
                {
                    if(s[z[id]].r[j]==Min)
                    {
                        printf("%d ",Min);
                        if(j==1) printf("A
    ");
                        if(j==2) printf("C
    ");
                        if(j==3) printf("M
    ");
                        if(j==4) printf("E
    ");
                        break;
                    }
                }
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5496966.html
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