Binary String Matching

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3

11

1001110110

101

110010010010001

1010

110100010101011 

样例输出

3

0

3 

#include <stdio.h>
#include <string.h>

int main(){
    int T;
    char a[11];
    char temp[11];
    char b[1001];
    int a_length;
    int b_length;
    int i;
    int amount;
    
    scanf("%d",&T);
    
    while(T--){
        scanf("%s%s",a,b);
        a_length=strlen(a);
        b_length=strlen(b);
        
        amount=0;
        for(i=0;i<b_length-a_length+1;i++){
            memset(temp,0,11);
            strncpy(temp,&b[i],a_length);
            
            if(strcmp(temp,a)==0){
                amount++;
            }
        }
        printf("%d
",amount);
    }
    return 0;
}