https://pintia.cn/problem-sets/994805342720868352/problems/994805415005503488
Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1k1×p2k2×⋯×pmkm.
Input Specification:
Each input file contains one test case which gives a positive integer N in the range of long int.
Output Specification:
Factor N in the format N =
p1^
k1*
p2^
k2*
…*
pm^
km, where pi's are prime factors of N in increasing order, and the exponent ki is the number of pi -- hence when there is only one pi, ki is 1 and must NOT be printed out.
Sample Input:
97532468
Sample Output:
97532468=2^2*11*17*101*1291
代码:
#include <bits/stdc++.h> using namespace std; long int P; int prime[500010]; int main() { memset(prime, 1, sizeof(prime)); for(int i = 2; i * i <= 500010; i ++) for(int j = 2; j * i < 500010; j ++) prime[j * i] = 0; scanf("%ld", &P); printf("%ld=", P); if(P == 1) printf("1"); bool First = false; for(int i = 2; P >= 2; i ++) { int cnt = 0, flag = 0; while(prime[i] && P % i == 0) { cnt ++; P /= i; flag = 1; } if(flag) { if(First) printf("*"); printf("%d", i); First = true; } if(cnt > 1) printf("^%d", cnt); } return 0; }
素数表! Get