• 50. Pow(x, n)(二分查找)


    50. Pow(x, n)
    Medium

    Implement pow(xn), which calculates x raised to the power n (xn).

    Example 1:

    Input: 2.00000, 10
    Output: 1024.00000
    

    Example 2:

    Input: 2.10000, 3
    Output: 9.26100
    

    Example 3:

    Input: 2.00000, -2
    Output: 0.25000
    Explanation: 2-2 = 1/22 = 1/4 = 0.25
    

    Note:

    • -100.0 < x < 100.0
    • n is a 32-bit signed integer, within the range [−231, 231 − 1]
    class Solution {
    public:
        double myPow(double x, int n) {
            if (n==-2147483648) return Pow(x,n+1)/x;
            else return Pow(x,n);
            
        }
        double Pow(double x, int n) {
            if (x==1.0 || x==0.0) return x;
            if(n > 0) {
                double res = myPow(x,n/2);
                if (n%2==0) return res*res;
                else return res*res*x;
            } else if (n < 0) {
                double res = myPow(x,-n/2);
                if(((-n)%2)==0) return 1/(res*res);
                else return 1/(res*res*x);
            } else {
                return 1;
            }
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/zle1992/p/12527779.html
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