• 17. *的字母组合


    给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。答案可以按 任意顺序 返回。

    给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。

    示例 1:

    输入:digits = "23"
    输出:["ad","ae","af","bd","be","bf","cd","ce","cf"]
    示例 2:

    输入:digits = ""
    输出:[]
    示例 3:

    输入:digits = "2"
    输出:["a","b","c"]

    class Solution {
        public List<String> letterCombinations(String digits) {
            List<String> list = new ArrayList<>();
            String[] s = new String[digits.length()];
            int M = digits.length();
            if (s.length == 0)
            {
                return list;
            } 
            for (int i = 0; i < digits.length();i++)
            {
                switch (digits.charAt(i))
                {
                    case '2': s[i] = "abc"; break;
                    case '3': s[i] = "def"; break;
                    case '4': s[i] = "ghi"; break;
                    case '5': s[i] = "jkl"; break;
                    case '6': s[i] = "mno"; break;
                    case '7': s[i] = "pqrs"; break;
                    case '8': s[i] = "tuv"; break;
                    case '9': s[i] = "wxyz"; break;
                 }
            }
            list = getStringWithFor(s, 0 ,list, "");
            return list;
        }
    
        private static List<String> getStringWithFor(String[] s, int i, List<String> list, String stemp)
        {
            if (i < s.length - 1)
            {
                for (int j = 0; j < s[i].length(); j++)
                {
                    list = getStringWithFor(s, i + 1, list, stemp + s[i].charAt(j));
                }
                i++;
            }else{
                for (int j = 0; j < s[i].length(); j++)
                {
                    list.add(stemp + s[i].charAt(j));
                }
            }
            return list;
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/ziytong/p/14998564.html
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