• BZOJ 3894 文理分科


    ....最小割,建三列点。

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<queue>
    #define maxv 50050
    #define maxe 2000050
    #define maxn 105
    #define inf 1000000007
    using namespace std;
    int n,m,a[maxn][maxn],b[maxn][maxn],c[maxn][maxn],d[maxn][maxn];
    int dis[maxv],tot=0,id[maxn][maxn][4],nume=1,g[maxv],sum=0,s,t;
    struct edge
    {
        int v,f,nxt;
    }e[maxe];
    queue <int> q;
    void addedge(int u,int v,int f)
    {
        e[++nume].v=v;e[nume].f=f;e[nume].nxt=g[u];g[u]=nume;
        e[++nume].v=u;e[nume].f=0;e[nume].nxt=g[v];g[v]=nume;
    }
    void build()
    {
        s=0;t=++tot;
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
            {
                addedge(s,id[i][j][1],a[i][j]);addedge(id[i][j][1],t,b[i][j]);
                addedge(s,id[i][j][2],c[i][j]);addedge(id[i][j][3],t,d[i][j]);
                addedge(id[i][j][2],id[i][j][1],inf);addedge(id[i][j][1],id[i][j][3],inf);
                if (i>1) {addedge(id[i-1][j][2],id[i][j][1],inf);addedge(id[i][j][1],id[i-1][j][3],inf);}
                if (i<n) {addedge(id[i+1][j][2],id[i][j][1],inf);addedge(id[i][j][1],id[i+1][j][3],inf);}
                if (j>1) {addedge(id[i][j-1][2],id[i][j][1],inf);addedge(id[i][j][1],id[i][j-1][3],inf);}
                if (j<m) {addedge(id[i][j+1][2],id[i][j][1],inf);addedge(id[i][j][1],id[i][j+1][3],inf);}
            }
    }
    bool bfs()
    {
        for (int i=s;i<=t;i++) dis[i]=inf;
        dis[s]=0;q.push(s);
        while (!q.empty())
        {
            int head=q.front();q.pop();
            for (int i=g[head];i;i=e[i].nxt)
            {
                int v=e[i].v;
                if (dis[v]>dis[head]+1 && e[i].f>0)
                {
                    dis[v]=dis[head]+1;
                    q.push(v);
                }
            }
        }
        return dis[t]!=inf;
    }
    int dinic(int x,int low)
    {
        if (x==t) return low;
        int ret=0;
        for (int i=g[x];i && low;i=e[i].nxt)
        {
            int v=e[i].v;
            if (e[i].f>0 && dis[v]==dis[x]+1)
            {
                int dd=dinic(v,min(low,e[i].f));
                low-=dd;ret+=dd;e[i].f-=dd;e[i^1].f+=dd;
            }
        }
        if (!ret) dis[x]=inf;
        return ret;
    }
    int main()
    {
        scanf("%d%d",&n,&m);
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
                scanf("%d",&a[i][j]);
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
                scanf("%d",&b[i][j]);
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
                scanf("%d",&c[i][j]);
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
                scanf("%d",&d[i][j]);
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
            {
                id[i][j][1]=++tot;id[i][j][2]=++tot;id[i][j][3]=++tot;
                sum+=a[i][j]+b[i][j]+c[i][j]+d[i][j];
            }
        build();
        while (bfs()) sum-=dinic(s,inf);
        printf("%d
    ",sum);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ziliuziliu/p/6640538.html
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