BZOJ 1221 软件开发

厉害了我的哥。。这建图。。

感谢http://www.cnblogs.com/rausen/p/4176729.html

这个建图的重点在于把需求和剩下的毛巾分开。

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#define maxv 2050
#define maxn 1050
#define maxe 1000050
#define inf 2000000000
using namespace std;
int n,a,b,f,fa,fb,N[maxn],dis[maxv],nume=1,g[maxv],pree[maxv],prev[maxv],s,t;
bool vis[maxv];
queue <int> q;
struct edge
{
    int v,f,c,nxt;
}e[maxe];
void addedge(int u,int v,int f,int c)
{
    e[++nume].v=v;e[nume].f=f;e[nume].c=c;e[nume].nxt=g[u];g[u]=nume;
    e[++nume].v=u;e[nume].f=0;e[nume].c=-c;e[nume].nxt=g[v];g[v]=nume;
}
void build()
{
    s=0;t=2*n+1;
    for (int i=1;i<=n;i++)
    {
        addedge(s,i,N[i],0);addedge(i+n,t,N[i],0);
        addedge(s,i+n,inf,f);
        if (i+a+1<=n) addedge(i,i+a+n+1,inf,fa);
        if (i+b+1<=n) addedge(i,i+b+n+1,inf,fb);
    }
    for (int i=1;i<=n-1;i++) addedge(i+n,i+n+1,inf,0);
}
bool spfa()
{
    for (int i=s;i<=t;i++) {pree[i]=prev[i]=-1;dis[i]=inf;vis[i]=false;}
    q.push(s);vis[s]=true;dis[s]=0;
    while (!q.empty())
    {
        int head=q.front();q.pop();
        for (int i=g[head];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if ((e[i].f) && (dis[v]>dis[head]+e[i].c))
            {
                dis[v]=dis[head]+e[i].c;
                pree[v]=i;prev[v]=head;
                if (!vis[v]) {q.push(v);vis[v]=true;}
            }
        }
        vis[head]=false;
    }
    if (dis[t]==inf) return false;
    return true;
}
int dinic()
{
    int u=t,low=inf;
    while (u!=s)
    {
        low=min(low,e[pree[u]].f);
        u=prev[u];
    }
    u=t;
    while (u!=s)
    {
        e[pree[u]].f-=low;e[pree[u]^1].f+=low;
        u=prev[u];
    }
    return dis[t]*low;
}
int main()
{
    scanf("%d%d%d%d%d%d",&n,&a,&b,&f,&fa,&fb);
    for (int i=1;i<=n;i++) scanf("%d",&N[i]);
    build();
    int min_cost=0;
    while (spfa()) min_cost+=dinic();
    printf("%d
",min_cost);
    return 0;
}