leetcode:Maximum Depth of Binary Tree

1、

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Given a binary tree as follow:

  1
 /  
2   3
   / 
  4   5

The maximum depth is 3.

2、左右左右的遍历，求最大值

3、

public class Solution {
    public int maxDepth(TreeNode root) {
        if (root == null) {
            return 0;
        }
        //遍历求值：求最大值
        int left = maxDepth(root.left);
        int right = maxDepth(root.right);
        return Math.max(left, right) + 1;
    }
}

// version 2: Traverse

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     * @param root: The root of binary tree.
     * @return: An integer.
     */
    private int depth;
    
    public int maxDepth(TreeNode root) {
        depth = 0;
        helper(root, 1);
        
        return depth;
    }
    
    private void helper(TreeNode node, int curtDepth) {
        if (node == null) {
            return;
        }
        
        if (curtDepth > depth) {
            depth = curtDepth;
        }
        
        helper(node.left, curtDepth + 1);
        helper(node.right, curtDepth + 1);
    }
}