Codeforces_496_E_贪心

http://codeforces.com/problemset/problem/496/E

这好像叫序列混合贪心，简单地讲，用歌去匹配最符合条件的人。用了multiset，重载了<，加快寻找最符合条件的人的速度。

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<set>
using namespace std;

struct song{
public:
    int low,high,flag,num;
    friend bool operator<(const song x,const song y)
    {
        return x.high < y.high;
    }
}a[200010];
int ans[100005],counts[100005];

bool cmp(song x,song y)
{
    if(x.low != y.low)  return x.low < y.low;
    return x.flag < y.flag;
}

int main()
{
    multiset<song> s;
    multiset<song>::iterator it;
    int n,m;
    cin >> n;
    for(int i = 1;i <= n;i++)
    {
        cin >> a[i].low >> a[i].high;
        a[i].flag = 1;
        a[i].num = i;
    }
    cin >> m;
    for(int i = n+1;i <= m+n;i++)
    {
        cin >> a[i].low >> a[i].high >> counts[i-n];
        a[i].flag = 0;
        a[i].num = i-n;
    }

    sort(a+1,a+1+m+n,cmp);
    s.clear();
    for(int i = 1;i <= m+n;i++)
    {
        if(a[i].flag)
        {
            it = s.lower_bound(a[i]);
            if(it == s.end())
            {
                cout << "NO" << endl;
                return 0;
            }
            else
            {
                ans[a[i].num] = it->num;
                counts[it->num]--;
                if(!counts[it->num])
                {
                    s.erase(it);
                }
            }
        }
        else
        {
            s.insert(a[i]);
        }
    }
    cout << "YES" << endl;
    int i;
    for(i = 1;i < n;i++)
    {
        cout << ans[i] << " ";
    }
    cout << ans[i] << endl;
    return 0;

}