题目:
不同的二叉搜索树:给定一个整数 n,求以 1 ... n 为节点组成的二叉搜索树有多少种?
思路:
找规律,使用动态规划模板。
程序:
class Solution: def numTrees(self, n: int) -> int: if n <= 0: return 0 auxiliary = [1] * (n + 1) for index in range(2, n + 1): auxiliary_result = 0 index1 = 0 index2 = index - 1 while index1 < index2: auxiliary_result += 2 * auxiliary[index1] * auxiliary[index2] index1 += 1 index2 -= 1 if index1 == index2: auxiliary_result += auxiliary[index1] * auxiliary[index2] auxiliary[index] = auxiliary_result return auxiliary[-1]