题目链接:http://poj.org/problem?id=1204
从字符矩阵的边缘字符扩展匹配分别记录最小值。
1 //STATUS:C++_AC_704MS_12432KB 2 #include<stdio.h> 3 #include<stdlib.h> 4 #include<string.h> 5 #include<math.h> 6 #include<iostream> 7 #include<string> 8 #include<algorithm> 9 #include<vector> 10 #include<queue> 11 #include<stack> 12 #include<map> 13 #include<set> 14 using namespace std; 15 //define 16 #define pii pair<int,int> 17 #define mem(a,b) memset(a,b,sizeof(a)) 18 #define lson l,mid,rt<<1 19 #define rson mid+1,r,rt<<1|1 20 #define PI acos(-1.0) 21 //typedef 22 typedef __int64 LL; 23 typedef unsigned __int64 ULL; 24 //const 25 const int N=1010; 26 const int INF=0x3f3f3f3f; 27 const int MOD=100000,STA=8000010; 28 const LL LNF=1LL<<60; 29 const double EPS=1e-8; 30 const double OO=1e15; 31 //Daily Use ... 32 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;} 33 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;} 34 template<class T> inline T Min(T a,T b){return a<b?a:b;} 35 template<class T> inline T Max(T a,T b){return a>b?a:b;} 36 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);} 37 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);} 38 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));} 39 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));} 40 //End 41 42 int dx[8]={-1,-1,0,1,1,1,0,-1}; 43 int dy[8]={0,1,1,1,0,-1,-1,-1}; 44 char ma[]="ABCDEFGH"; 45 char s[N][N],temp[N]; 46 int ch[N*300][26]; 47 int val[N*300],f[N*300],last[N*300],ans[N][3],len[N]; 48 int sz,n,m,w; 49 50 void init(){sz=1;mem(ch[0],0);} 51 inline int idx(char c){return c-'A';} 52 void insert(char *s,int v){ 53 int i,len=strlen(s),id,u=0; 54 for(i=0;i<len;i++){ 55 id=idx(s[i]); 56 if(!ch[u][id]){ 57 mem(ch[sz],0); 58 val[sz]=0; 59 ch[u][id]=sz++; 60 } 61 u=ch[u][id]; 62 } 63 val[u]=v; 64 } 65 66 void getFail() 67 { 68 int u,c,r; 69 queue<int> q; 70 f[0]=0; 71 for(c=0;c<26;c++){ 72 u=ch[0][c]; 73 if(u){f[u]=0;last[u]=0;q.push(u);} 74 } 75 while(!q.empty()){ 76 r=q.front();q.pop(); 77 for(c=0;c<26;c++){ 78 u=ch[r][c]; 79 if(!u){ch[r][c]=ch[f[r]][c];continue;} 80 q.push(u); 81 f[u]=ch[f[r]][c]; 82 last[u]=val[f[u]]?f[u]:last[f[u]]; 83 } 84 } 85 } 86 87 void judge(int u,int x,int y,int dir) 88 { 89 if(u){ 90 int nx,ny,v=val[u]; 91 nx=x-dx[dir]*(len[v]-1); 92 ny=y-dy[dir]*(len[v]-1); 93 if(nx<ans[v][0] || ( nx==ans[v][0] && ny<ans[v][1] ) 94 || (nx==ans[v][0] && ny==ans[v][1] && dir<ans[v][2]) ){ 95 ans[v][0]=nx; 96 ans[v][1]=ny; 97 ans[v][2]=dir; 98 } 99 judge(last[u],x,y,dir); 100 } 101 } 102 103 void find(int x,int y,int dir) 104 { 105 int c,u; 106 for(u=0;x>=0&&x<n && y>=0&&y<m;x+=dx[dir],y+=dy[dir]){ 107 c=idx(s[x][y]); 108 u=ch[u][c]; 109 if(val[u]){judge(u,x,y,dir);} 110 else if(last[u]){judge(last[u],x,y,dir);} 111 } 112 } 113 114 void slove() 115 { 116 int i; 117 for(i=0;i<m;i++){ 118 find(0,i,4);find(0,i,3);find(0,i,5); 119 find(n-1,i,0);find(n-1,i,7);find(n-1,i,1); 120 } 121 122 for(i=0;i<n;i++){ 123 find(i,0,2);find(i,0,1);find(i,0,3); 124 find(i,m-1,6);find(i,m-1,5);find(i,m-1,7); 125 } 126 } 127 128 int main() 129 { 130 // freopen("in.txt","r",stdin); 131 int i,j,k; 132 while(~scanf("%d%d%d",&n,&m,&w)) 133 { 134 mem(ans,INF); 135 for(i=0;i<n;i++){ 136 scanf("%s",s[i]); 137 } 138 init(); 139 for(i=1;i<=w;i++){ 140 scanf("%s",temp); 141 len[i]=strlen(temp); 142 insert(temp,i); 143 } 144 getFail(); 145 slove(); 146 147 for(i=1;i<=w;i++){ 148 printf("%d %d %c\n",ans[i][0],ans[i][1],ma[ans[i][2]]); 149 } 150 } 151 return 0; 152 }