1.
int a[2][2][3]={{{1,2,3},{4,5,6}},{{7,8,9},{10,11,12}}}; int *ptr=(int*)(&a+1); printf("%d %d",*(int*)(a+1),*(ptr-1)); 答案:7 12
2.
char str[] = "Hello"; char *p=str; int n = 10; printf("%d,%d,%d,",sizeof(str),sizeof(p),sizeof(n)); 答案:6, 4,4,
3.
#include <stdio.h> #include <stdio.h> int main() { int* pint = 0; pint += 6; printf("%d\n", pint); } 两个点: 1.在初始化中只有地址才能赋值给指针,因此*int p=0是指p指向地址0x00。 2.int型数占4个字节,因此加6表示偏移了24个字节,结果的地址应为0x18,即是24.
4.
unsigned char *p1; unsigned long *p2; p1=(unsigned char *)0x801000; p2=(unsigned long *)0x801000; printf("%X,%X",p1+5,p2+5); 答案: 0x801005,0x801014
5.